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A sphere of radius r has uniformly distributed charge q a spherical portion of radius r by 2 is cut from it to form a cavity as shown in the figure electric potential at the centre of cavity is show all calculations?
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A sphere of radius r has uniformly distributed charge q a spherical po...
Calculation of Electric Potential at the Centre of the Cavity
Gauss's Law
- According to Gauss's Law, the electric field inside a conductor is zero.
Electric Potential Inside the Cavity
- Since the electric field is zero inside the conductor, the electric potential inside the cavity is constant and equal to the electric potential at the surface of the cavity.
Electric Potential Due to the Original Sphere
- The electric potential at a distance r from the center of a uniformly charged sphere of radius r is given by V = k * q / r, where k is the electrostatic constant.
Electric Potential at the Surface of the Cavity
- The electric potential at the surface of the cavity is the same as the electric potential at a distance r from the center of the original sphere.
- Therefore, the electric potential at the surface of the cavity is V = k * q / r.
Electric Potential at the Centre of the Cavity
- Since the electric potential inside the cavity is constant and equal to the potential at the surface of the cavity, the electric potential at the center of the cavity is also V = k * q / r.
Therefore, the electric potential at the center of the cavity is V = k * q / r.
Gauss's Law
- According to Gauss's Law, the electric field inside a conductor is zero.
Electric Potential Inside the Cavity
- Since the electric field is zero inside the conductor, the electric potential inside the cavity is constant and equal to the electric potential at the surface of the cavity.
Electric Potential Due to the Original Sphere
- The electric potential at a distance r from the center of a uniformly charged sphere of radius r is given by V = k * q / r, where k is the electrostatic constant.
Electric Potential at the Surface of the Cavity
- The electric potential at the surface of the cavity is the same as the electric potential at a distance r from the center of the original sphere.
- Therefore, the electric potential at the surface of the cavity is V = k * q / r.
Electric Potential at the Centre of the Cavity
- Since the electric potential inside the cavity is constant and equal to the potential at the surface of the cavity, the electric potential at the center of the cavity is also V = k * q / r.
Therefore, the electric potential at the center of the cavity is V = k * q / r.
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A sphere of radius r has uniformly distributed charge q a spherical portion of radius r by 2 is cut from it to form a cavity as shown in the figure electric potential at the centre of cavity is show all calculations?
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A sphere of radius r has uniformly distributed charge q a spherical portion of radius r by 2 is cut from it to form a cavity as shown in the figure electric potential at the centre of cavity is show all calculations? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A sphere of radius r has uniformly distributed charge q a spherical portion of radius r by 2 is cut from it to form a cavity as shown in the figure electric potential at the centre of cavity is show all calculations? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A sphere of radius r has uniformly distributed charge q a spherical portion of radius r by 2 is cut from it to form a cavity as shown in the figure electric potential at the centre of cavity is show all calculations?.
A sphere of radius r has uniformly distributed charge q a spherical portion of radius r by 2 is cut from it to form a cavity as shown in the figure electric potential at the centre of cavity is show all calculations? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A sphere of radius r has uniformly distributed charge q a spherical portion of radius r by 2 is cut from it to form a cavity as shown in the figure electric potential at the centre of cavity is show all calculations? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A sphere of radius r has uniformly distributed charge q a spherical portion of radius r by 2 is cut from it to form a cavity as shown in the figure electric potential at the centre of cavity is show all calculations?.
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