A sphere of radius r has uniformly distributed charge q a spherical portion of radius r by 2 is cut from it to form a cavity as shown in the figure electric potential at the centre of cavity is show all calculations?

Question

Answer

Calculation of Electric Potential at the Centre of the Cavity

Gauss's Law
- According to Gauss's Law, the electric field inside a conductor is zero.

Electric Potential Inside the Cavity
- Since the electric field is zero inside the conductor, the electric potential inside the cavity is constant and equal to the electric potential at the surface of the cavity.

Electric Potential Due to the Original Sphere
- The electric potential at a distance r from the center of a uniformly charged sphere of radius r is given by V = k * q / r, where k is the electrostatic constant.

Electric Potential at the Surface of the Cavity
- The electric potential at the surface of the cavity is the same as the electric potential at a distance r from the center of the original sphere.
- Therefore, the electric potential at the surface of the cavity is V = k * q / r.

Electric Potential at the Centre of the Cavity
- Since the electric potential inside the cavity is constant and equal to the potential at the surface of the cavity, the electric potential at the center of the cavity is also V = k * q / r.
Therefore, the electric potential at the center of the cavity is V = k * q / r.

Top Courses for Physics

Suggested Free Tests

Related Content

Schools

Competitive Examinations

Quick Access Links

Technical Exams