Sum of oxidation state of br in products reaction of br2 with hot and conc NaOH is?

Question

Answer

Explanation of Sum of Oxidation State of Br in Products of Reaction of Br2 with Hot and Conc NaOH:

Reaction:
- Br2 + 2NaOH → NaBr + NaBrO3 + H2O

Initial Oxidation State of Br in Br2:
- Br2 has an oxidation state of 0

Final Oxidation States of Br in Products:
1. NaBr: Br has an oxidation state of -1
2. NaBrO3: Br has an oxidation state of +5

Sum of Oxidation States of Br in Products:
- (-1) + (+5) = +4

Explanation:
- In the reaction between Br2 and hot and concentrated NaOH, Br undergoes reduction to form NaBr with an oxidation state of -1 and oxidation to form NaBrO3 with an oxidation state of +5.
- The sum of the oxidation states of Br in the products is +4, which indicates the overall change in the oxidation state of Br in the reaction.
- This change in oxidation state is due to the transfer of electrons during the redox reaction between Br2 and NaOH.

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