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The odds in favour of one student Passing a test are 3:7. The odds against another student Passing at are 3:5. The probability that both pass is?
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The odds in favour of one student Passing a test are 3:7. The odds aga...
Calculating the Probability that both students pass the test:
- First, let's calculate the individual probabilities of each student passing the test based on the odds given:
- For the student with odds in favor of 3:7, the probability of passing is 3/(3+7) = 3/10 = 0.3 or 30%.
- For the student with odds against 3:5, the probability of passing is 5/(3+5) = 5/8 = 0.625 or 62.5%.
- Next, we need to find the probability that both students pass the test. Since the students' performances are independent of each other, we can multiply their individual probabilities to find the overall probability:
- Probability that both students pass = Probability of student 1 passing * Probability of student 2 passing
- Probability that both students pass = 0.3 * 0.625 = 0.1875 or 18.75%.
Therefore, the probability that both students pass the test is 18.75%. This means that there is an 18.75% chance that both students will pass the test based on the given odds.
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The odds in favour of one student Passing a test are 3:7. The odds against another student Passing at are 3:5. The probability that both pass is?
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