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The odds in favour of one student passing a test are 3:7.The odds against another student passing at are 3:5. The probability that both fail is
  • a)
    7/16
  • b)
    21/80
  • c)
    9/80
  • d)
    3/16
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The odds in favour of one student passing a test are 3:7.The odds agai...
Given Information:
- The odds in favour of one student passing a test are 3:7.
- The odds against another student passing at are 3:5.

To Find: The probability that both fail.

Solution:
Let's assume there are two students A and B.

- For student A, the odds in favor of passing the test are 3:7. This means:
- The probability of passing the test = 3/(3+7) = 3/10
- The probability of failing the test = 7/(3+7) = 7/10
- For student B, the odds against passing the test are 3:5. This means:
- The probability of failing the test = 3/(3+5) = 3/8
- The probability of passing the test = 5/(3+5) = 5/8

We need to find the probability that both students fail the test.
- P(A fails and B fails) = P(A fails) x P(B fails)
- P(A fails) = Probability of student A failing the test = 7/10
- P(B fails) = Probability of student B failing the test = 3/8
- P(A fails and B fails) = (7/10) x (3/8) = 21/80

Therefore, the probability that both students fail the test is 21/80. Hence, option B is the correct answer.
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The odds in favour of one student passing a test are 3:7.The odds against another student passing at are 3:5. The probability that both fail isa)7/16b)21/80c)9/80d)3/16Correct answer is option 'B'. Can you explain this answer?
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