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Consider the equation C+ O2=CO2.If 3.011×10^22 carbon atoms are reacting then what mass of CO2 gas will be produced?
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Consider the equation C+ O2=CO2.If 3.011×10^22 carbon atoms are reacti...
Calculating the mass of CO2 produced
Carbon dioxide (CO2) is produced when carbon (C) reacts with oxygen (O2) according to the equation: C + O2 → CO2.
Step 1: Determine the molar ratio
From the balanced chemical equation, we can see that 1 mole of carbon reacts with 1 mole of oxygen to produce 1 mole of carbon dioxide.
Step 2: Calculate the number of moles of carbon
Given that 3.011×10^22 carbon atoms are reacting, we need to convert this number of carbon atoms to moles. The molar mass of carbon is approximately 12 g/mol.
Number of moles of carbon = Number of atoms of carbon / Avogadro's number
Number of moles of carbon = 3.011×10^22 / 6.022×10^23 ≈ 0.05 moles
Step 3: Calculate the mass of CO2 produced
Using the molar ratio from step 1, we can see that 1 mole of carbon dioxide has a molar mass of approximately 44 g/mol (12 g/mol for carbon + 32 g/mol for oxygen).
Number of moles of CO2 produced = Number of moles of carbon
Mass of CO2 produced = Number of moles of CO2 produced × Molar mass of CO2
Mass of CO2 produced = 0.05 moles × 44 g/mol ≈ 2.2 grams
Therefore, when 3.011×10^22 carbon atoms react, approximately 2.2 grams of CO2 gas will be produced.
Carbon dioxide (CO2) is produced when carbon (C) reacts with oxygen (O2) according to the equation: C + O2 → CO2.
Step 1: Determine the molar ratio
From the balanced chemical equation, we can see that 1 mole of carbon reacts with 1 mole of oxygen to produce 1 mole of carbon dioxide.
Step 2: Calculate the number of moles of carbon
Given that 3.011×10^22 carbon atoms are reacting, we need to convert this number of carbon atoms to moles. The molar mass of carbon is approximately 12 g/mol.
Number of moles of carbon = Number of atoms of carbon / Avogadro's number
Number of moles of carbon = 3.011×10^22 / 6.022×10^23 ≈ 0.05 moles
Step 3: Calculate the mass of CO2 produced
Using the molar ratio from step 1, we can see that 1 mole of carbon dioxide has a molar mass of approximately 44 g/mol (12 g/mol for carbon + 32 g/mol for oxygen).
Number of moles of CO2 produced = Number of moles of carbon
Mass of CO2 produced = Number of moles of CO2 produced × Molar mass of CO2
Mass of CO2 produced = 0.05 moles × 44 g/mol ≈ 2.2 grams
Therefore, when 3.011×10^22 carbon atoms react, approximately 2.2 grams of CO2 gas will be produced.
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Consider the equation C+ O2=CO2.If 3.011×10^22 carbon atoms are reacting then what mass of CO2 gas will be produced?
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Consider the equation C+ O2=CO2.If 3.011×10^22 carbon atoms are reacting then what mass of CO2 gas will be produced? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about Consider the equation C+ O2=CO2.If 3.011×10^22 carbon atoms are reacting then what mass of CO2 gas will be produced? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the equation C+ O2=CO2.If 3.011×10^22 carbon atoms are reacting then what mass of CO2 gas will be produced?.
Consider the equation C+ O2=CO2.If 3.011×10^22 carbon atoms are reacting then what mass of CO2 gas will be produced? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about Consider the equation C+ O2=CO2.If 3.011×10^22 carbon atoms are reacting then what mass of CO2 gas will be produced? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the equation C+ O2=CO2.If 3.011×10^22 carbon atoms are reacting then what mass of CO2 gas will be produced?.
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