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Find the pairs of consecutive even positive integers both of which are smaller than 10 and their sum of more than 11
  • a)
    (4, 8)
  • b)
    (6, 8)
  • c)
    (6, 8) and (4, 8)
  • d)
    (6, 4)(4, 2)
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Find the pairs of consecutive even positive integers both of which are...
Let x be the smaller of the two consecutive even positive integers, then the other even integer is x + 2. 
 Given x < 10  and x + (x + 2) > 11.  
⇒ x < 10, and 2x + 2 > 11.  
⇒ x < 10, 2x > 9 
⇒ x < 10, x > 9/2 
⇒ 10 < x > 9/2   
∴ the required parity even integers is (6, 8)
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Community Answer
Find the pairs of consecutive even positive integers both of which are...
Solution:

To find the pairs of consecutive even positive integers less than 12 and not 10, we can list down all the even positive integers less than 12 and then eliminate the pair (8,10), which violates the given condition.

The even positive integers less than 12 are:
2, 4, 6, 8, 10

Eliminating the pair (8,10), we get:
2, 4, 6

The pairs of consecutive even positive integers less than 12 and not 10 are:
(2,4), (4,6), and (6,8)

Out of these three pairs, only (6,8) satisfies the condition that both integers should be less than 12 and not 10. Therefore, the correct answer is option (B) (6,8).

Therefore, option 'B' is the correct answer.
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Find the pairs of consecutive even positive integers both of which are smaller than 10 and their sum of more than 11a)(4, 8)b)(6, 8)c)(6, 8) and (4, 8)d)(6, 4)(4, 2)Correct answer is option 'B'. Can you explain this answer?
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