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Pairs of consecutive even positive integers, both of which are larger than 7 such that their sum is less than 28, are
- a)(8, 9), (9, 10), (10, 11)
- b)(8, 10), (10, 12)
- c)(8, 10), (10, 12), (12, 14)
- d)(8, 10), (10, 12), (12, 14), (14, 16)
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Pairs of consecutive even positive integers, both of which are larger ...
Let x be the smaller of the two consecutive even positive integers .
Then the other integer is x+2.
Since both the integers are larger than 7,x > 7 ....(1)
Also the sum of the two integers is less than 28.
x + (x + 2) < 28
⇒ 2x + 2 < 28
⇒ 2x < 28 − 2
⇒ 2x < 26
=> x < 13…...(2)
From(1) and (2), we get
7 < x <13
Since x is an even number, x can take the values 8, 10 and 12.
Thus the required possible pairs are (8,10),(10,12) and (12,8).
Then the other integer is x+2.
Since both the integers are larger than 7,x > 7 ....(1)
Also the sum of the two integers is less than 28.
x + (x + 2) < 28
⇒ 2x + 2 < 28
⇒ 2x < 28 − 2
⇒ 2x < 26
=> x < 13…...(2)
From(1) and (2), we get
7 < x <13
Since x is an even number, x can take the values 8, 10 and 12.
Thus the required possible pairs are (8,10),(10,12) and (12,8).
Most Upvoted Answer
Pairs of consecutive even positive integers, both of which are larger ...
Let x be the smaller of the two consecutive even positive integers .
Then the other integer is x+2.
Since both the integers are larger than 7,x > 7 ....(1)
Also the sum of the two integers is less than 28.
x + (x + 2) < 28
⇒ 2x + 2 < 28
⇒ 2x < 28 − 2
⇒ 2x < 26
=> x < 13…...(2)
From(1) and (2), we get
7 < x <13
Since x is an even number, x can take the values 8, 10 and 12.
Thus the required possible pairs are (8,10),(10,12) and (12,8).
Then the other integer is x+2.
Since both the integers are larger than 7,x > 7 ....(1)
Also the sum of the two integers is less than 28.
x + (x + 2) < 28
⇒ 2x + 2 < 28
⇒ 2x < 28 − 2
⇒ 2x < 26
=> x < 13…...(2)
From(1) and (2), we get
7 < x <13
Since x is an even number, x can take the values 8, 10 and 12.
Thus the required possible pairs are (8,10),(10,12) and (12,8).
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Pairs of consecutive even positive integers, both of which are larger ...
I think in option (a) : 8&9 are consecutive +be integers but 9 is an odd no.... in option (d) the sum of 14 & 16 is greater than 28....as per condition it must be less then 28.. and in option (b) ..... I think option c , has more pair then it so.... can be possible. answer is (c)
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Pairs of consecutive even positive integers, both of which are larger than 7 such that their sum is less than 28, area)(8, 9), (9, 10), (10, 11)b)(8, 10), (10, 12)c)(8, 10), (10, 12), (12, 14)d)(8, 10), (10, 12), (12, 14), (14, 16)Correct answer is option 'C'. Can you explain this answer?
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Pairs of consecutive even positive integers, both of which are larger than 7 such that their sum is less than 28, area)(8, 9), (9, 10), (10, 11)b)(8, 10), (10, 12)c)(8, 10), (10, 12), (12, 14)d)(8, 10), (10, 12), (12, 14), (14, 16)Correct answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Pairs of consecutive even positive integers, both of which are larger than 7 such that their sum is less than 28, area)(8, 9), (9, 10), (10, 11)b)(8, 10), (10, 12)c)(8, 10), (10, 12), (12, 14)d)(8, 10), (10, 12), (12, 14), (14, 16)Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Pairs of consecutive even positive integers, both of which are larger than 7 such that their sum is less than 28, area)(8, 9), (9, 10), (10, 11)b)(8, 10), (10, 12)c)(8, 10), (10, 12), (12, 14)d)(8, 10), (10, 12), (12, 14), (14, 16)Correct answer is option 'C'. Can you explain this answer?.
Pairs of consecutive even positive integers, both of which are larger than 7 such that their sum is less than 28, area)(8, 9), (9, 10), (10, 11)b)(8, 10), (10, 12)c)(8, 10), (10, 12), (12, 14)d)(8, 10), (10, 12), (12, 14), (14, 16)Correct answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Pairs of consecutive even positive integers, both of which are larger than 7 such that their sum is less than 28, area)(8, 9), (9, 10), (10, 11)b)(8, 10), (10, 12)c)(8, 10), (10, 12), (12, 14)d)(8, 10), (10, 12), (12, 14), (14, 16)Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Pairs of consecutive even positive integers, both of which are larger than 7 such that their sum is less than 28, area)(8, 9), (9, 10), (10, 11)b)(8, 10), (10, 12)c)(8, 10), (10, 12), (12, 14)d)(8, 10), (10, 12), (12, 14), (14, 16)Correct answer is option 'C'. Can you explain this answer?.
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