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The ultimate tensile strength of a material is 400 MPa and the elongation up to maximum load is 35%. If the material obeys power law of hardening, then the true stress-true strain relation (stress in MPa) in the plastic deformation range is:
- a)σ = 540ε0.30
- b)σ = 775ε0.30
- c)σ = 540ε0.35
- d)σ = 775ε0.35
Correct answer is option 'B'. Can you explain this answer?
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The ultimate tensile strength of a material is 400 MPa and the elongat...
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The ultimate tensile strength of a material is 400 MPa and the elongat...
The power law of hardening is given by:
σ = kε^n
Where σ is the true stress, ε is the true strain, k is a constant, and n is the strain hardening exponent.
To find k and n, we can use the given information:
At the maximum load, σ = 400 MPa and ε = 0.35.
Substituting these values into the equation:
400 = k(0.35)^n
We need another data point to solve for k and n. Let's assume that at a strain of 0.5, the true stress is 200 MPa.
Substituting these values into the equation:
200 = k(0.5)^n
Now we have two equations and two unknowns (k and n). Dividing the two equations:
400/200 = (0.35/0.5)^n
2 = 0.7^n
Taking the logarithm of both sides:
n = log(2)/log(0.7) ≈ 2.449
Substituting this value into one of the equations:
400 = k(0.35)^2.449
k ≈ 1,180.9
Now we can write the true stress-true strain relation:
σ = 1,180.9ε^2.449
σ = kε^n
Where σ is the true stress, ε is the true strain, k is a constant, and n is the strain hardening exponent.
To find k and n, we can use the given information:
At the maximum load, σ = 400 MPa and ε = 0.35.
Substituting these values into the equation:
400 = k(0.35)^n
We need another data point to solve for k and n. Let's assume that at a strain of 0.5, the true stress is 200 MPa.
Substituting these values into the equation:
200 = k(0.5)^n
Now we have two equations and two unknowns (k and n). Dividing the two equations:
400/200 = (0.35/0.5)^n
2 = 0.7^n
Taking the logarithm of both sides:
n = log(2)/log(0.7) ≈ 2.449
Substituting this value into one of the equations:
400 = k(0.35)^2.449
k ≈ 1,180.9
Now we can write the true stress-true strain relation:
σ = 1,180.9ε^2.449
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The ultimate tensile strength of a material is 400 MPa and the elongat...
Get value of true strain, den get true stress wid d given data using d usual traditional formula..den use d power law of hardening, where u wil put d value of strain hardening component equals to ur engineering strain(its for necking to occur after strain hardening), den from power law get value of K..den put d same value in power law..n get d answer..Sorry unable to upload d image of explanation bcz of this app issue..
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The ultimate tensile strength of a material is 400 MPa and the elongation up to maximum load is 35%. If the material obeys power law of hardening, then the true stress-true strain relation (stress in MPa) in the plastic deformation range is:a)σ= 540ε0.30b)σ= 775ε0.30c)σ= 540ε0.35d)σ= 775ε0.35Correct answer is option 'B'. Can you explain this answer?
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The ultimate tensile strength of a material is 400 MPa and the elongation up to maximum load is 35%. If the material obeys power law of hardening, then the true stress-true strain relation (stress in MPa) in the plastic deformation range is:a)σ= 540ε0.30b)σ= 775ε0.30c)σ= 540ε0.35d)σ= 775ε0.35Correct answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about The ultimate tensile strength of a material is 400 MPa and the elongation up to maximum load is 35%. If the material obeys power law of hardening, then the true stress-true strain relation (stress in MPa) in the plastic deformation range is:a)σ= 540ε0.30b)σ= 775ε0.30c)σ= 540ε0.35d)σ= 775ε0.35Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The ultimate tensile strength of a material is 400 MPa and the elongation up to maximum load is 35%. If the material obeys power law of hardening, then the true stress-true strain relation (stress in MPa) in the plastic deformation range is:a)σ= 540ε0.30b)σ= 775ε0.30c)σ= 540ε0.35d)σ= 775ε0.35Correct answer is option 'B'. Can you explain this answer?.
The ultimate tensile strength of a material is 400 MPa and the elongation up to maximum load is 35%. If the material obeys power law of hardening, then the true stress-true strain relation (stress in MPa) in the plastic deformation range is:a)σ= 540ε0.30b)σ= 775ε0.30c)σ= 540ε0.35d)σ= 775ε0.35Correct answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about The ultimate tensile strength of a material is 400 MPa and the elongation up to maximum load is 35%. If the material obeys power law of hardening, then the true stress-true strain relation (stress in MPa) in the plastic deformation range is:a)σ= 540ε0.30b)σ= 775ε0.30c)σ= 540ε0.35d)σ= 775ε0.35Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The ultimate tensile strength of a material is 400 MPa and the elongation up to maximum load is 35%. If the material obeys power law of hardening, then the true stress-true strain relation (stress in MPa) in the plastic deformation range is:a)σ= 540ε0.30b)σ= 775ε0.30c)σ= 540ε0.35d)σ= 775ε0.35Correct answer is option 'B'. Can you explain this answer?.
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The ultimate tensile strength of a material is 400 MPa and the elongation up to maximum load is 35%. If the material obeys power law of hardening, then the true stress-true strain relation (stress in MPa) in the plastic deformation range is:a)σ= 540ε0.30b)σ= 775ε0.30c)σ= 540ε0.35d)σ= 775ε0.35Correct answer is option 'B'. Can you explain this answer?, a detailed solution for The ultimate tensile strength of a material is 400 MPa and the elongation up to maximum load is 35%. If the material obeys power law of hardening, then the true stress-true strain relation (stress in MPa) in the plastic deformation range is:a)σ= 540ε0.30b)σ= 775ε0.30c)σ= 540ε0.35d)σ= 775ε0.35Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of The ultimate tensile strength of a material is 400 MPa and the elongation up to maximum load is 35%. If the material obeys power law of hardening, then the true stress-true strain relation (stress in MPa) in the plastic deformation range is:a)σ= 540ε0.30b)σ= 775ε0.30c)σ= 540ε0.35d)σ= 775ε0.35Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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