I proton moves with a speed of 3 m/s in circular orbit in X5 plane in ...
To understand the motion of a proton under the influence of a magnetic field and an electric field, we need to analyze the forces acting on it.
Magnetic Force and Circular Motion
- A proton moving in a magnetic field experiences a magnetic force given by the Lorentz force equation:
**F_mag = q(v × B)**
where:
- **q** = charge of the proton (approximately \(1.6 \times 10^{-19}\) C)
- **v** = velocity of the proton
- **B** = magnetic field strength (1 T in the z-direction)
- The magnetic force causes the proton to move in a circular path in the X-Y plane. The velocity \(v\) is directed along the X-axis, and the magnetic field \(B\) is directed along the Z-axis. The radius of the circular motion can be determined from the centripetal force required to keep the proton in the circle.
Effect of Electric Field
- When an electric field \(E\) of 1 V/m is applied in the positive Y direction, the proton experiences an additional force:
**F_electric = qE**
- Here, the electric force acts in the positive Y direction.
- The net force acting on the proton becomes a combination of the magnetic force (which acts perpendicular to both velocity and magnetic field) and the electric force.
Drift Velocity Calculation
- The application of the electric field leads to a phenomenon known as the **E × B drift**. The drift velocity \(v_d\) of the proton can be calculated using the formula:
**v_d = E / B**
- Substituting \(E = 1 \, \text{V/m}\) and \(B = 1 \, \text{T}\):
**v_d = 1 / 1 = 1 \, \text{m/s}**
- This drift velocity indicates that the center of the circular orbit moves at a speed of **1 m/s along the positive X direction** due to the combined effects of the electric and magnetic fields.