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If the zeroes of the polynomial x ^ 2 + px + q are double in value to the zerves of 2x ^ 2 - 5x - 3 find the value of p and q?
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If the zeroes of the polynomial x ^ 2 + px + q are double in value to ...
Step 1: Identify the Roots of the Second Polynomial
To find the roots of the polynomial \(2x^2 - 5x - 3\), we can use the quadratic formula:
\[
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\]
Here, \(a = 2\), \(b = -5\), and \(c = -3\).

Calculating the Discriminant
- \(b^2 - 4ac = (-5)^2 - 4(2)(-3) = 25 + 24 = 49\)

Finding the Roots
\[
x = \frac{5 \pm \sqrt{49}}{4} = \frac{5 \pm 7}{4}
\]
- Roots: \(x_1 = 3\), \(x_2 = -\frac{1}{2}\)

Step 2: Determine the Roots of the First Polynomial
Given that the roots of \(x^2 + px + q\) are double the roots of the second polynomial:
- New roots: \(2x_1 = 6\) and \(2x_2 = -1\)

Step 3: Formulate the Polynomial
The polynomial with roots \(6\) and \(-1\) can be expressed as:
\[
x^2 - (6 - 1)x + (6)(-1)
\]
This simplifies to:
\[
x^2 - 5x - 6
\]

Step 4: Identify p and q
From the polynomial \(x^2 + px + q\):
- \(p = -5\)
- \(q = -6\)

Final Values
- \(p = -5\)
- \(q = -6\)
These are the values of \(p\) and \(q\) for the polynomial \(x^2 + px + q\).
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If the zeroes of the polynomial x ^ 2 + px + q are double in value to the zerves of 2x ^ 2 - 5x - 3 find the value of p and q?
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