How many signals does the unsaturated ketone(CH3)2CHCH2C(O)CH=CH2have ...
Understanding the Structure
The compound in question, (CH3)2CHCH2C(O)CH=CH2, is an unsaturated ketone. To determine the number of signals for both 1H and 13C NMR spectra, we need to analyze its structure and identify the unique environments for hydrogen and carbon atoms.
1H NMR Signals
- The hydrogen atoms can be grouped based on their unique environments:
- **CH3 groups (2)**: The two methyl (CH3) groups attached to the isopropyl carbon contribute **2 signals**.
- **CH2 group (1)**: The methylene (CH2) group adjacent to the carbonyl contributes **1 signal**.
- **H on carbon adjacent to carbonyl (1)**: The hydrogen on the carbon adjacent to the carbonyl (C=O) contributes **1 signal**.
- **Alkenic hydrogens (2)**: The two hydrogens on the alkene (CH=CH2) contribute **2 signals**.
Thus, the total number of unique 1H signals is **6**.
13C NMR Signals
- Now, let’s analyze the carbon atoms:
- **Two CH3 groups**: Each CH3 contributes **1 signal** (total **2 signals**).
- **One CH (connected to the carbonyl)**: This carbon contributes **1 signal**.
- **One CH2 (next to the CH)**: This carbon contributes **1 signal**.
- **One carbonyl carbon (C=O)**: This contributes **1 signal**.
- **Two carbons from the alkene (C=C)**: Each contributes **1 signal** (total **2 signals**).
Thus, the total number of unique 13C signals is **6**.
Conclusion
In summary, the unsaturated ketone (CH3)2CHCH2C(O)CH=CH2 has **6 unique 1H NMR signals** and **6 unique 13C NMR signals**. Therefore, the correct answer is option **B**: six 1H signals and six 13C signals.