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A does half as much work as B in three-fourth of the time. If they together can complete a work in 18 days, find how long B alone would take to do the work?
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A does half as much work as B in three-fourth of the time. If they tog...
Understanding the Problem
To solve the problem, let's define the work done by A and B, and their respective working rates.

Work Relationship
- Let the amount of work that B can complete in one day be represented as \( b \).
- Therefore, A does half as much work as B in three-fourths of the time. So, A's work rate is:
- \( a = \frac{1}{2}b \) (since A does half the work of B)
Using the time relation, if B completes work in \( t_B \) days, then A completes it in \( \frac{3}{4}t_B \) days.

Combined Work Rate
- The total work can be expressed as:
- \( W = b \times t_B \) for B
- \( W = a \times \frac{3}{4}t_B = \frac{1}{2}b \times \frac{3}{4}t_B = \frac{3}{8}bt_B \) for A
Since they can complete the work together in 18 days:
- The combined work rate:
- \( a + b = \frac{3}{8}b + b = \frac{11}{8}b \)
Thus, the total work done together in 18 days is:
- \( 18 \times \frac{11}{8}b = W \)

Finding B's Time Alone
We already established that:
- \( W = b \times t_B \)
Setting the equal expressions for work:
- \( 18 \times \frac{11}{8}b = b \times t_B \)
By cancelling \( b \) from both sides (assuming \( b \neq 0 \)):
- \( t_B = \frac{18 \times 11}{8} \)
- \( t_B = 24.75 \) days

Conclusion
Thus, B alone would take approximately **24.75 days** to complete the work.
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A does half as much work as B in three-fourth of the time. If they together can complete a work in 18 days, find how long B alone would take to do the work?
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