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A and B together complete a work in 6 days. If time required to complete 90% of work by A is equal to time required to complete 60% of work by of B, then find the time taken by A to complete 50% of the same work?
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A and B together complete a work in 6 days. If time required to comple...
Given information:
- A and B together complete a work in 6 days.
- Time required to complete 90% of work by A is equal to time required to complete 60% of work by B.

Calculations:
Let the total work be 100 units.
- A's 90% work = 90 units
- B's 60% work = 60 units

Time taken by A and B to complete their respective work:
- Let time taken by A to complete 90 units = x days
- Let time taken by B to complete 60 units = y days
According to the given data:
- A's work rate = 90/x
- B's work rate = 60/y

Combined work rate of A and B:
- A and B together complete 100 units of work in 6 days, so their combined work rate = 100/6 = 16.67 units/day
Since A and B work together,
(90/x) + (60/y) = 16.67
Given that time taken by A to complete 90% of the work is equal to time taken by B to complete 60% of the work:
x = y
Substitute y with x in the equation:
(90/x) + (60/x) = 16.67
150/x = 16.67
x = 150/16.67
x ≈ 9 days
Therefore, A takes 9 days to complete 90% of the work, which means A takes 9/0.9 = 10 days to complete 100% of the work.

Time taken by A to complete 50% of the work:
To complete 50% of the work, A would take half the time taken to complete 100% of the work.
Therefore, time taken by A to complete 50% of the work = 10/2 = 5 days.
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A and B together complete a work in 6 days. If time required to complete 90% of work by A is equal to time required to complete 60% of work by of B, then find the time taken by A to complete 50% of the same work?
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