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Circular gears P and Q start rotating at the same time at constant speeds. Gear P makes 10 revolutions per minute and Gear Q makes 40 revolutions per minute. How many seconds after the gears start rotating will gear Q have made exactly 6 more revolutions than gear P ?
  • a)
    6
  • b)
    8
  • c)
    10
  • d)
    12
  • e)
    15
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Circular gears P and Q start rotating at the same time at constant spe...
Understanding Gear Revolutions
To solve the problem, we need to determine the number of revolutions made by each gear over time.

Revolutions per Minute
- Gear P: 10 revolutions per minute (rpm)
- Gear Q: 40 revolutions per minute (rpm)

Revolutions per Second
- Gear P: \( \frac{10 \text{ revolutions}}{60 \text{ seconds}} = \frac{1}{6} \text{ revolutions per second} \)
- Gear Q: \( \frac{40 \text{ revolutions}}{60 \text{ seconds}} = \frac{2}{3} \text{ revolutions per second} \)

Revolutions Over Time
- Let \( t \) be the time in seconds after the gears start rotating.
- Revolutions by Gear P: \( \text{Revolutions}_P = \frac{1}{6}t \)
- Revolutions by Gear Q: \( \text{Revolutions}_Q = \frac{2}{3}t \)

Finding the Difference in Revolutions
- We want to find when Gear Q has made exactly 6 more revolutions than Gear P.
- Set up the equation:
\[ \text{Revolutions}_Q = \text{Revolutions}_P + 6 \]
\[ \frac{2}{3}t = \frac{1}{6}t + 6 \]

Solving the Equation
1. Clear the fractions by multiplying the entire equation by 6:
\[ 6 \cdot \frac{2}{3}t = 6 \cdot \frac{1}{6}t + 36 \]
\[ 4t = t + 36 \]
2. Isolate \( t \):
\[ 4t - t = 36 \]
\[ 3t = 36 \]
\[ t = 12 \]

Conclusion
Thus, Gear Q will have made exactly 6 more revolutions than Gear P after **12 seconds**. The correct answer is option **D**.
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