A can do a piece of work in 30 days B in 50 days and C in 40 days. If ...
Work Efficiency of A, B, and C
A can complete the work in 30 days, so A's work rate is:
- Work Rate of A: 1/30 work/day
B can complete the work in 50 days, so B's work rate is:
- Work Rate of B: 1/50 work/day
C can complete the work in 40 days, so C's work rate is:
- Work Rate of C: 1/40 work/day
Combined Work of A and B
When A works with B for one day:
- Combined Work Rate (A + B): (1/30 + 1/50)
To combine these fractions, find the LCM of 30 and 50, which is 150:
- Work Rate of A + B: (5/150 + 3/150) = 8/150 = 4/75 work/day
Combined Work of A and C
When A works with C for the next day:
- Combined Work Rate (A + C): (1/30 + 1/40)
Finding the LCM of 30 and 40, which is 120:
- Work Rate of A + C: (4/120 + 3/120) = 7/120 work/day
Work Done in Two Days
In two days, the total work done is:
- Total Work in 2 Days: (4/75 + 7/120)
To combine these, find the LCM of 75 and 120, which is 300:
- Work Done: (16/300 + 17.5/300) = 33.5/300 = 67/600 work
Days to Complete the Work
The total work is 1 (the whole piece):
- Days Required: 1 / (67/600) = 600/67 ≈ 8.96 days
Thus, the work will be completed in approximately:
- Final Answer: 9 days (considering rounding).