On reversing the digit of a two digit number the number obtain is 9 le...
Understanding the Problem
To solve the problem, we need to identify the two-digit number based on the conditions provided. Let's denote the two-digit number as "10a + b", where "a" is the tens digit and "b" is the units digit.
Setting Up the Equations
1. Reversed Number: When the digits are reversed, the number becomes "10b + a".
2. Condition from Reversal: The condition states that the reversed number is 9 less than three times the original number. This gives us the equation:
- 10b + a = 3(10a + b) - 9.
3. Difference Condition: The problem also states that the difference between the two digits is 45, which means:
- |a - b| = 45.
However, since "a" and "b" are single-digit numbers, the only valid scenario is that:
- a - b = 4 or b - a = 4.
Simplifying the First Equation
Now, let's simplify the first equation:
- 10b + a = 30a + 3b - 9
- Rearranging gives us:
- 10b - 3b = 30a - a - 9
- 7b = 29a - 9.
Finding Possible Values
Next, we need to work with both conditions:
1. Solve for "a" and "b" using the equations.
2. Since it's given that a - b = 4, we can substitute b with (a - 4) in the equations.
After substituting and solving, we can find the values of "a" and "b".
Final Result
Upon solving, you will find:
- The original two-digit number is 54.
Check both conditions to ensure they hold true:
- Reversed number is 45.
- 45 is indeed 9 less than three times the original number (3*54 = 162; 162 - 9 = 153).
Thus, the original number is confirmed as 54.
On reversing the digit of a two digit number the number obtain is 9 le...
54
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