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Natural abundances of 12C and 13C isotopes of C are 99% and 1% respectively assuming they only contribute to molar weight of C2F4 . %of C2F4 having molar mass 101 is?
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Natural abundances of 12C and 13C isotopes of C are 99% and 1% respect...
Understanding the Molar Mass of C2F4
To determine the percentage of C2F4 molecules with a molar mass of 101 g/mol, we need to consider the isotopes of carbon and their contributions to the overall molar mass.
Isotope Contributions
- Carbon (C) has two stable isotopes:
- 12C: 99% natural abundance
- 13C: 1% natural abundance
- Molar mass of isotopes:
- 12C = 12 g/mol
- 13C = 13 g/mol
Molar Mass Calculation of C2F4
1. Calculating Molar Mass for 12C:
- For C2 (both atoms as 12C):
- Molar mass = 2 * 12 = 24 g/mol
- For F (Fluorine):
- Molar mass of F = 19 g/mol
- For F4: 4 * 19 = 76 g/mol
- Total for 12C: 24 + 76 = 100 g/mol
2. Calculating Molar Mass for 13C:
- For C2 (both atoms as 13C):
- Molar mass = 2 * 13 = 26 g/mol
- For F (as above):
- Total for 13C: 26 + 76 = 102 g/mol
Percentage Calculation
- We can find the weighted average molar mass:
- Contribution of 12C:
- 99% * 100 g/mol = 99 g/mol
- Contribution of 13C:
- 1% * 102 g/mol = 1.02 g/mol
- Total average molar mass: 99 + 1.02 = 100.02 g/mol
Conclusion: Percentage of C2F4 with Molar Mass 101 g/mol
- Since the average molar mass of C2F4 is approximately 100.02 g/mol, the percentage of C2F4 with a molar mass of 101 g/mol is negligible (close to 0%).
- Therefore, C2F4 primarily contributes to a molar mass around 100 g/mol, with 101 g/mol being a minor fraction, largely derived from the rare 13C isotope.
To determine the percentage of C2F4 molecules with a molar mass of 101 g/mol, we need to consider the isotopes of carbon and their contributions to the overall molar mass.
Isotope Contributions
- Carbon (C) has two stable isotopes:
- 12C: 99% natural abundance
- 13C: 1% natural abundance
- Molar mass of isotopes:
- 12C = 12 g/mol
- 13C = 13 g/mol
Molar Mass Calculation of C2F4
1. Calculating Molar Mass for 12C:
- For C2 (both atoms as 12C):
- Molar mass = 2 * 12 = 24 g/mol
- For F (Fluorine):
- Molar mass of F = 19 g/mol
- For F4: 4 * 19 = 76 g/mol
- Total for 12C: 24 + 76 = 100 g/mol
2. Calculating Molar Mass for 13C:
- For C2 (both atoms as 13C):
- Molar mass = 2 * 13 = 26 g/mol
- For F (as above):
- Total for 13C: 26 + 76 = 102 g/mol
Percentage Calculation
- We can find the weighted average molar mass:
- Contribution of 12C:
- 99% * 100 g/mol = 99 g/mol
- Contribution of 13C:
- 1% * 102 g/mol = 1.02 g/mol
- Total average molar mass: 99 + 1.02 = 100.02 g/mol
Conclusion: Percentage of C2F4 with Molar Mass 101 g/mol
- Since the average molar mass of C2F4 is approximately 100.02 g/mol, the percentage of C2F4 with a molar mass of 101 g/mol is negligible (close to 0%).
- Therefore, C2F4 primarily contributes to a molar mass around 100 g/mol, with 101 g/mol being a minor fraction, largely derived from the rare 13C isotope.
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Natural abundances of 12C and 13C isotopes of C are 99% and 1% respectively assuming they only contribute to molar weight of C2F4 . %of C2F4 having molar mass 101 is?
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Natural abundances of 12C and 13C isotopes of C are 99% and 1% respectively assuming they only contribute to molar weight of C2F4 . %of C2F4 having molar mass 101 is? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Natural abundances of 12C and 13C isotopes of C are 99% and 1% respectively assuming they only contribute to molar weight of C2F4 . %of C2F4 having molar mass 101 is? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Natural abundances of 12C and 13C isotopes of C are 99% and 1% respectively assuming they only contribute to molar weight of C2F4 . %of C2F4 having molar mass 101 is?.
Natural abundances of 12C and 13C isotopes of C are 99% and 1% respectively assuming they only contribute to molar weight of C2F4 . %of C2F4 having molar mass 101 is? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Natural abundances of 12C and 13C isotopes of C are 99% and 1% respectively assuming they only contribute to molar weight of C2F4 . %of C2F4 having molar mass 101 is? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Natural abundances of 12C and 13C isotopes of C are 99% and 1% respectively assuming they only contribute to molar weight of C2F4 . %of C2F4 having molar mass 101 is?.
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