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An oil of kinematic viscosity 0.5 stokes flows through a pipe of 4 cm diameter. The flow is critical at a velocity of about
  • a)
    1.5 m/s
  • b)
    2.2 m/s
  • c)
    2.5 m/s
  • d)
    3 m/s
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
An oil of kinematic viscosity 0.5 stokes flows through a pipe of 4 cm ...
For critical flow Reynold's No. = 2000 = (density x velocity x diameter) ÷ ( dynamic viscosity) So...2000= (v x d) ÷ (kinematic viscosity)2000 = (v x 0.04) ÷ (0.5/10000) v = 2.5 m/s So option C is correct.
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Community Answer
An oil of kinematic viscosity 0.5 stokes flows through a pipe of 4 cm ...
Given data:
Kinematic viscosity (v) = 0.5 stokes
Diameter of pipe (D) = 4 cm

Critical velocity is the velocity at which the flow changes from laminar to turbulent. It is given by the formula:

Vc = (f*v*D)/2ρ

Where,
f = friction factor
ρ = density of oil

Calculation:
The Reynolds number for critical flow is 2000.
Reynolds number (Re) = (ρ*Vc*D)/v = 2000

Substituting the given values, we get:

Vc = (f*v*D)/2ρ = 2.5 m/s (approx.)

Therefore, the critical velocity for the given oil flowing through a pipe of 4 cm diameter is 2.5 m/s.
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An oil of kinematic viscosity 0.5 stokes flows through a pipe of 4 cm diameter. The flow is critical at a velocity of abouta)1.5 m/sb)2.2 m/sc)2.5 m/sd)3 m/sCorrect answer is option 'C'. Can you explain this answer?
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