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A fluid of kinematic viscosity 0.4 cm2/sec flows through a 8 cm diameter pipe. The maximum velocity for laminar flow will be
- a)less than 1 m/sec
- b)1 m/sec
- c). 1.5 m/sec
- d)2 m/sec
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
A fluid of kinematic viscosity 0.4 cm2/sec flows through a 8 cm diamet...
Maximum Reynold's number for laminar flow = 2000
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A fluid of kinematic viscosity 0.4 cm2/sec flows through a 8 cm diamet...
Given data:
Kinematic viscosity of fluid = 0.4 cm2/sec
Diameter of pipe = 8 cm
To find: Maximum velocity for laminar flow
Formula used:
The Reynolds number (Re) is used to determine the flow regime of a fluid. It is defined as the ratio of inertial forces to viscous forces within a fluid. The formula to calculate Reynolds number is:
Re = (ρVD)/μ
where:
ρ = density of fluid
V = velocity of fluid
D = diameter of pipe
μ = dynamic viscosity of fluid
For laminar flow, Reynolds number is less than 2000.
Calculation:
The density of fluid is not given, so we assume it to be that of water, which is 1000 kg/m3.
Converting kinematic viscosity from cm2/sec to m2/sec:
0.4 cm2/sec = 0.00004 m2/sec
Diameter of pipe = 8 cm = 0.08 m
μ = ρν
μ = 1000 x 0.00004
μ = 0.04 kg/m-s
Re = (ρVD)/μ
Re = (1000 x V x 0.08)/0.04
Re = 2000V
For laminar flow, Re < />
2000V < />
V < 1="" />
Therefore, the maximum velocity for laminar flow will be less than 1 m/sec.
Hence, option (a) is the correct answer.
Kinematic viscosity of fluid = 0.4 cm2/sec
Diameter of pipe = 8 cm
To find: Maximum velocity for laminar flow
Formula used:
The Reynolds number (Re) is used to determine the flow regime of a fluid. It is defined as the ratio of inertial forces to viscous forces within a fluid. The formula to calculate Reynolds number is:
Re = (ρVD)/μ
where:
ρ = density of fluid
V = velocity of fluid
D = diameter of pipe
μ = dynamic viscosity of fluid
For laminar flow, Reynolds number is less than 2000.
Calculation:
The density of fluid is not given, so we assume it to be that of water, which is 1000 kg/m3.
Converting kinematic viscosity from cm2/sec to m2/sec:
0.4 cm2/sec = 0.00004 m2/sec
Diameter of pipe = 8 cm = 0.08 m
μ = ρν
μ = 1000 x 0.00004
μ = 0.04 kg/m-s
Re = (ρVD)/μ
Re = (1000 x V x 0.08)/0.04
Re = 2000V
For laminar flow, Re < />
2000V < />
V < 1="" />
Therefore, the maximum velocity for laminar flow will be less than 1 m/sec.
Hence, option (a) is the correct answer.
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A fluid of kinematic viscosity 0.4 cm2/sec flows through a 8 cm diameter pipe. The maximum velocity for laminar flow will bea)less than 1 m/secb)1 m/secc). 1.5 m/secd)2 m/secCorrect answer is option 'B'. Can you explain this answer?
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