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A 1000 kg, a 1000 kg car traveling at 20 m per second.Comes to a stop in 5 seconds.When the brakes are applied , what is the average horse exerted by the brakes on the car?
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A 1000 kg, a 1000 kg car traveling at 20 m per second.Comes to a stop ...
Understanding the Problem
To find the average force exerted by the brakes on the car, we first need to calculate the deceleration and then use it to find the force.
Given Data
- Mass of the car (m): 1000 kg
- Initial velocity (u): 20 m/s
- Final velocity (v): 0 m/s
- Time (t): 5 seconds
Calculating Deceleration
- Deceleration (a) can be calculated using the formula:
a = (v - u) / t
a = (0 - 20) / 5
a = -4 m/s² (negative indicates slowing down)
Calculating Force
- The force (F) exerted by the brakes can be calculated using Newton’s second law:
F = m * a
F = 1000 kg * (-4 m/s²)
F = -4000 N (negative indicates force acting in the opposite direction)
Converting Force to Horsepower
- To find the average horsepower (hp), we can use the formula:
1 horsepower = 745.7 watts
Power (P) = F * v (average velocity during braking)
Average velocity = (u + v) / 2 = (20 + 0) / 2 = 10 m/s
P = 4000 N * 10 m/s = 40000 watts
Horsepower = 40000 / 745.7 ≈ 53.6 hp
Conclusion
- The average force exerted by the brakes on the car is 4000 N.
- The average horsepower exerted by the brakes is approximately 53.6 hp.
This calculation illustrates the effective braking power needed to stop a vehicle in motion.
To find the average force exerted by the brakes on the car, we first need to calculate the deceleration and then use it to find the force.
Given Data
- Mass of the car (m): 1000 kg
- Initial velocity (u): 20 m/s
- Final velocity (v): 0 m/s
- Time (t): 5 seconds
Calculating Deceleration
- Deceleration (a) can be calculated using the formula:
a = (v - u) / t
a = (0 - 20) / 5
a = -4 m/s² (negative indicates slowing down)
Calculating Force
- The force (F) exerted by the brakes can be calculated using Newton’s second law:
F = m * a
F = 1000 kg * (-4 m/s²)
F = -4000 N (negative indicates force acting in the opposite direction)
Converting Force to Horsepower
- To find the average horsepower (hp), we can use the formula:
1 horsepower = 745.7 watts
Power (P) = F * v (average velocity during braking)
Average velocity = (u + v) / 2 = (20 + 0) / 2 = 10 m/s
P = 4000 N * 10 m/s = 40000 watts
Horsepower = 40000 / 745.7 ≈ 53.6 hp
Conclusion
- The average force exerted by the brakes on the car is 4000 N.
- The average horsepower exerted by the brakes is approximately 53.6 hp.
This calculation illustrates the effective braking power needed to stop a vehicle in motion.
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A 1000 kg, a 1000 kg car traveling at 20 m per second.Comes to a stop in 5 seconds.When the brakes are applied , what is the average horse exerted by the brakes on the car?
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A 1000 kg, a 1000 kg car traveling at 20 m per second.Comes to a stop in 5 seconds.When the brakes are applied , what is the average horse exerted by the brakes on the car? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A 1000 kg, a 1000 kg car traveling at 20 m per second.Comes to a stop in 5 seconds.When the brakes are applied , what is the average horse exerted by the brakes on the car? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 1000 kg, a 1000 kg car traveling at 20 m per second.Comes to a stop in 5 seconds.When the brakes are applied , what is the average horse exerted by the brakes on the car?.
A 1000 kg, a 1000 kg car traveling at 20 m per second.Comes to a stop in 5 seconds.When the brakes are applied , what is the average horse exerted by the brakes on the car? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A 1000 kg, a 1000 kg car traveling at 20 m per second.Comes to a stop in 5 seconds.When the brakes are applied , what is the average horse exerted by the brakes on the car? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 1000 kg, a 1000 kg car traveling at 20 m per second.Comes to a stop in 5 seconds.When the brakes are applied , what is the average horse exerted by the brakes on the car?.
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