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If ab + bc + ca = 0, then find 1/a2-bc + 1/b2 – ca + 1/c2- ab
  • a)
    π
  • b)
    0
  • c)
    -1
  • d)
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
If ab + bc + ca = 0, then find1/a2-bc + 1/b2– ca + 1/c2- aba)&pi...
Given ab+bc+ca=0 and asked to find value 1/(a2-bc
) + 1/(c2-ab) + 1/(a2-bc)Put -ac = ab + bc ; -ab = ac+ bc and -bc =ab + 
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Community Answer
If ab + bc + ca = 0, then find1/a2-bc + 1/b2– ca + 1/c2- aba)&pi...
Given ab + bc + ca = 0, we can rewrite the expression 1/a^2 - bc as:

1/a^2 - bc = (ab + bc + ca) / (a^2) - bc
= (ab + bc + ca - a^2 * bc) / (a^2)
= (ab + bc - a^2 * bc + ca) / (a^2)
= (b(a - ac) + c(a - ac)) / (a^2)
= (b - bc)(a - ac) / (a^2)
= b(1 - c)(a - ac) / (a^2)
= b(1 - c)(1 - ac) / a

Similarly, we can rewrite the expression 1/b^2 as:

1/b^2 = (ab + bc + ca) / (b^2)
= (ab + bc + ca - ab^2) / (b^2)
= (bc(a - ab) + ca(a - ab)) / (b^2)
= (c(a - ab) + a - ab) / (b)
= (1 - ab)(c - 1) / b

Therefore, the value of 1/a^2 - bc is b(1 - c)(1 - ac) / a and the value of 1/b^2 is (1 - ab)(c - 1) / b.
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If ab + bc + ca = 0, then find1/a2-bc + 1/b2– ca + 1/c2- aba)πb)0c)-1d)2πCorrect answer is option 'B'. Can you explain this answer?
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