The decreasing order of the first ionization energy of the following e...
Here electronic configurations of given elements ends like this. xe =5s2 4d10 5p6 As=4s2 3d10 4p3 Al=3s2 3p1 Be=2s2 xe have a complete octet among the 4,hence it have the highest ionozation enthalphy value.In case of As it have a half filled p orbital hence it has an half filled stability so it have more ionozation enthalphy than Al and Be.In case of Be electrons willremoved from s orbital while in case of Al electrons will removed from p orbital.S orbitals are penetrate towards nucleus than P. hence Be outer electron faces more attraction towards nucleus than p electron of Al.so ionozation enthalphy of Be is greater than Al. so the order will be Xe>As>Be>Al
The decreasing order of the first ionization energy of the following e...
Explanation:
The first ionization energy (IE) is the energy required to remove one mole of electrons from one mole of isolated gaseous atoms or ions in their ground state. The decreasing order of the first ionization energy of the following elements is given as Xe, As, Be, Al.
First ionization energy of Xenon (Xe):
Xenon is a noble gas and has a completely filled outermost shell. The first ionization energy of Xenon is high as it requires a lot of energy to remove an electron from a completely filled shell. Therefore, Xenon has the highest first ionization energy among the given elements.
First ionization energy of Arsenic (As):
Arsenic has 5 valence electrons and they are present in different energy levels. The valence electrons are held by the nucleus with different forces. Therefore, the first ionization energy of As is less than that of Xenon.
First ionization energy of Beryllium (Be):
Beryllium has 2 valence electrons and they are held very tightly by the nucleus due to its small size. Therefore, the first ionization energy of Be is greater than that of As.
First ionization energy of Aluminum (Al):
Aluminum has 3 valence electrons and they are held less tightly by the nucleus than that of Be. Therefore, the first ionization energy of Al is less than that of Be.
Decreasing order of first ionization energy:
From the above explanation, the decreasing order of the first ionization energy of the given elements is Xe > As > Be > Al. Therefore, option C, which has the correct order of Xe, As, and Be, is the correct answer.