If a unit charge is taken from one part to another part over an equipotential surface, then what is the change in electrostatic potential energy of the charge?a)10 Jb)100 Jc)1 Jd)0 JCorrect answer is option 'D'. Can you explain this answer?

Question

Answer

Equipotential surface means the potential on every. point on that surface is constant. it means the change in potential on equipotential surface is zero we know that... ( electrostatic potential energy = change in potential × charge.)... ... according to this electrostatic potential energy is zero

Answer

Potential difference is defined as the work done on unit charge.on epuipotential surface,∆V =0 W=0

Answer

As the defination tells equipotential surface has same value of potential on its every point means potencial difference for 2 points is zero as work done to move the charge is qV and V=0 so work is zero.Also the change in electrostatic potencial energy is zero.

Answer

Change in Electrostatic Potential Energy over an Equipotential Surface
Equipotential surfaces are surfaces in space where the electric potential is the same at every point. This implies that the work done in moving a charge along an equipotential surface is zero, as no external force is required to move the charge. Therefore, the change in electrostatic potential energy of a charge moving from one part to another over an equipotential surface is zero.

Explanation
When a unit charge is moved over an equipotential surface, the potential energy of the charge remains constant because the potential is the same at all points on the surface. Since the potential energy is directly related to the work done in moving the charge, and no work is done in moving the charge over an equipotential surface, the change in electrostatic potential energy is zero.

Mathematically
The change in electrostatic potential energy (∆U) is given by the formula:
∆U = q∆V
Where:
∆U = change in electrostatic potential energy
q = charge
∆V = change in potential
In this case, ∆V = 0 (as the charge is moved over an equipotential surface)
Therefore, ∆U = q * 0 = 0
Therefore, the change in electrostatic potential energy of the charge is 0 J.

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