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A body of mass 2 kg is hung on a spring balance mounted vertically in a lift. If the lift moves up with an acceleration equal to the acceleration due to gravity, the reading on the spring balance will be
a)5 kg
b)8 kg
c)7 kg
d)4 kg
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
A body of mass 2 kg is hung on a spring balance mounted vertically in ...
As the lift moves upwards but the spring feels itself at rest hence we need to compensate the non inertial frame by adding an appropriate pseudo force to treat it as an inertial frame. Hence the pseudo force to be applied acts on every mass in the lift which is equal to mass x acceleration (=g) downwards.
Hence the tension in the spring would be 40N (20 due to weight and 20 pseudo). Thus the reading would be 4kg.
Hence the tension in the spring would be 40N (20 due to weight and 20 pseudo). Thus the reading would be 4kg.
Most Upvoted Answer
A body of mass 2 kg is hung on a spring balance mounted vertically in ...
Solution:
Given, mass of the body, m = 2 kg
Acceleration due to gravity, g = 9.8 m/s²
When the lift moves upward with an acceleration equal to the acceleration due to gravity, the effective acceleration acting on the body will be:
a = g + a'
where a' is the acceleration of the lift
a' = g = 9.8 m/s²
a = 2g = 19.6 m/s²
Now, the reading on the spring balance will be equal to the weight of the body, which is given by:
W = mg
W = 2 × 9.8
W = 19.6 N
Therefore, the reading on the spring balance will be:
Reading = W/g
Reading = 19.6/9.8
Reading = 2 kg
Hence, the correct option is D.
Given, mass of the body, m = 2 kg
Acceleration due to gravity, g = 9.8 m/s²
When the lift moves upward with an acceleration equal to the acceleration due to gravity, the effective acceleration acting on the body will be:
a = g + a'
where a' is the acceleration of the lift
a' = g = 9.8 m/s²
a = 2g = 19.6 m/s²
Now, the reading on the spring balance will be equal to the weight of the body, which is given by:
W = mg
W = 2 × 9.8
W = 19.6 N
Therefore, the reading on the spring balance will be:
Reading = W/g
Reading = 19.6/9.8
Reading = 2 kg
Hence, the correct option is D.
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Community Answer
A body of mass 2 kg is hung on a spring balance mounted vertically in ...
Answer is 4kg.spring force=weight+pseudo force. F=2g+2g. reading=spring force/g 4g/g=4
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A body of mass 2 kg is hung on a spring balance mounted vertically in a lift. If the lift moves up with an acceleration equal to the acceleration due to gravity, the reading on the spring balance will bea)5 kgb)8 kgc)7 kgd)4 kgCorrect answer is option 'D'. Can you explain this answer?
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