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Obtain the Laplace Transform of the signal x (t) =e^(-at) Cos (wot) u(-t), and indicate its ROC.?
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Obtain the Laplace Transform of the signal x (t) =e^(-at) Cos (wot) u(...
Laplace Transform of the Signal
To find the Laplace Transform of the signal x(t) = e^(-at) cos(w0t) u(-t), we will follow the steps below:
Step 1: Definition of Laplace Transform
- The Laplace Transform is defined as:
L{x(t)} = ∫[0, ∞] e^(-st) x(t) dt
However, since x(t) is multiplied by the unit step function u(-t), we will consider the integral from -∞ to 0.
Step 2: Applying the Transform
- The Laplace Transform becomes:
L{x(t)} = ∫[-∞, 0] e^(-st) e^(-at) cos(w0t) dt
- This can be simplified to:
L{x(t)} = ∫[-∞, 0] e^(-(s + a)t) cos(w0t) dt
Step 3: Evaluating the Integral
- The integral can be evaluated using the standard formula for the Laplace Transform of cos:
L{cos(ωt)} = s / (s^2 + ω^2)
Thus, the result for our function becomes:
L{x(t)} = (s + a) / ((s + a)^2 + w0^2)
ROC (Region of Convergence)
- The ROC for this Laplace Transform is determined by the exponential decay factor e^(-at).
- Since x(t) is defined for t < 0="" (due="" to="" u(-t)),="" the="" roc="" will="" be="" re{s}="" />< />
Conclusion
- The Laplace Transform of x(t) = e^(-at) cos(w0t) u(-t) is:
L{x(t)} = (s + a) / ((s + a)^2 + w0^2)
- The ROC is Re{s} < -a.="" />
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Obtain the Laplace Transform of the signal x (t) =e^(-at) Cos (wot) u(-t), and indicate its ROC.?
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