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Two capacitors of capacitances 1mF and 3mF are charged to the same voltages 5V. They are connected in parallel with oppositely charged plates connected together. Then
  • a)
    Final common voltage will be 5V
  • b)
    Final common voltage will be 2.5 V
  • c)
    Heat produced in the circuit will be zero
  • d)
    Heat produced in the circuit will be 37.5mJ
Correct answer is option 'B,D'. Can you explain this answer?
Verified Answer
Two capacitors of capacitances 1mF and 3mF are charged to the same vol...
V=(C1V1−C2V2)/C1+C2
  =3×5−1×5/1+3
  = 2.5volt
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Two capacitors of capacitances 1mF and 3mF are charged to the same vol...
Final common voltage:
- When capacitors are connected in parallel, the voltage across them is the same.
- Since both capacitors are charged to 5V, the final common voltage will be 5V. Therefore, option (a) is incorrect.

Heat produced in the circuit:
- When capacitors are connected in parallel, the total capacitance of the combination is the sum of individual capacitances.
- In this case, the total capacitance is 1mF + 3mF = 4mF.
- When capacitors are connected in parallel, the total charge on the combination is the sum of individual charges.
- The charge on a capacitor is given by Q = CV, where Q is the charge, C is the capacitance, and V is the voltage.
- For the first capacitor, Q1 = (1mF)(5V) = 5mC.
- For the second capacitor, Q2 = (3mF)(5V) = 15mC.
- The total charge on the combination is Q = Q1 + Q2 = 5mC + 15mC = 20mC.
- The heat produced in a circuit is given by H = (1/2)CV^2, where H is the heat, C is the capacitance, and V is the voltage.
- The heat produced in the first capacitor is H1 = (1/2)(1mF)(5V)^2 = 12.5mJ.
- The heat produced in the second capacitor is H2 = (1/2)(3mF)(5V)^2 = 37.5mJ.
- The total heat produced in the circuit is H = H1 + H2 = 12.5mJ + 37.5mJ = 50mJ.
- Therefore, option (c) is incorrect and option (d) is correct.

In summary, the final common voltage will be 5V (option b is incorrect) and the heat produced in the circuit will be 50mJ (option d is correct).
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Two capacitors of capacitances 1mF and 3mF are charged to the same vol...
A
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Two capacitors of capacitances 1mF and 3mF are charged to the same voltages 5V. They are connected in parallel with oppositely charged plates connected together. Thena)Final common voltage will be 5Vb)Final common voltage will be 2.5 Vc)Heat produced in the circuit will be zerod)Heat produced in the circuit will be 37.5mJCorrect answer is option 'B,D'. Can you explain this answer?
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Two capacitors of capacitances 1mF and 3mF are charged to the same voltages 5V. They are connected in parallel with oppositely charged plates connected together. Thena)Final common voltage will be 5Vb)Final common voltage will be 2.5 Vc)Heat produced in the circuit will be zerod)Heat produced in the circuit will be 37.5mJCorrect answer is option 'B,D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Two capacitors of capacitances 1mF and 3mF are charged to the same voltages 5V. They are connected in parallel with oppositely charged plates connected together. Thena)Final common voltage will be 5Vb)Final common voltage will be 2.5 Vc)Heat produced in the circuit will be zerod)Heat produced in the circuit will be 37.5mJCorrect answer is option 'B,D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two capacitors of capacitances 1mF and 3mF are charged to the same voltages 5V. They are connected in parallel with oppositely charged plates connected together. Thena)Final common voltage will be 5Vb)Final common voltage will be 2.5 Vc)Heat produced in the circuit will be zerod)Heat produced in the circuit will be 37.5mJCorrect answer is option 'B,D'. Can you explain this answer?.
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