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If enthalpy of hydrogenation of C6H6(l) into C6H12(l) is –205 kJ and resonance energy of C6H6(l) is –152 kJ/mol then enthalpy of hydrogenation of is assume ΔHVap of C6H6(l), C6H8(l), C6H12(l) all are equal:
  • a)
    –535.5 kJ/mol
  • b)
    –238 kJ/mol
  • c)
    – 357 kJ/mol
  • d)
    –119 kJ/mol
Correct answer is option 'B'. Can you explain this answer?
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If enthalpy of hydrogenation of C6H6(l) into C6H12(l) is –205 kJ...
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If enthalpy of hydrogenation of C6H6(l) into C6H12(l) is –205 kJ and resonance energy of C6H6(l) is –152 kJ/mol then enthalpy of hydrogenation ofis assume ΔHVap of C6H6(l), C6H8(l), C6H12(l) all are equal:a)–535.5 kJ/molb)–238 kJ/molc)– 357 kJ/mold)–119 kJ/molCorrect answer is option 'B'. Can you explain this answer?
Question Description
If enthalpy of hydrogenation of C6H6(l) into C6H12(l) is –205 kJ and resonance energy of C6H6(l) is –152 kJ/mol then enthalpy of hydrogenation ofis assume ΔHVap of C6H6(l), C6H8(l), C6H12(l) all are equal:a)–535.5 kJ/molb)–238 kJ/molc)– 357 kJ/mold)–119 kJ/molCorrect answer is option 'B'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about If enthalpy of hydrogenation of C6H6(l) into C6H12(l) is –205 kJ and resonance energy of C6H6(l) is –152 kJ/mol then enthalpy of hydrogenation ofis assume ΔHVap of C6H6(l), C6H8(l), C6H12(l) all are equal:a)–535.5 kJ/molb)–238 kJ/molc)– 357 kJ/mold)–119 kJ/molCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If enthalpy of hydrogenation of C6H6(l) into C6H12(l) is –205 kJ and resonance energy of C6H6(l) is –152 kJ/mol then enthalpy of hydrogenation ofis assume ΔHVap of C6H6(l), C6H8(l), C6H12(l) all are equal:a)–535.5 kJ/molb)–238 kJ/molc)– 357 kJ/mold)–119 kJ/molCorrect answer is option 'B'. Can you explain this answer?.
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