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1.2 gm of carbon is burnt completely in oxygen (limited supply) to produce CO and C02. This mixture of gases is treated with solid 1205 (to know the amount of CO produced), the liberated iodine required 120 ml of 0.1 M hypo solution for complete titration. The % of carbon converted into CO is :
a)60%
b)100%
c)50%
d)70%
Correct answer is option 'D'. Can you explain this answer?
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Given information:
- Amount of carbon burnt completely = 1.2 gm
- Gases produced = CO and CO2
- The mixture is treated with solid 1205 to know the amount of CO produced
- The liberated iodine required 120 ml of 0.1 M hypo solution for complete titration
To find: The percentage of carbon converted into CO
Solution:
1. Balanced chemical equation for the combustion of carbon:
C + O2 -> CO2
2C + O2 -> 2CO (since both CO and CO2 are produced, it means that there was a limited supply of oxygen)
2. Calculation of moles of iodine used in the titration:
0.1 M hypo solution means that 0.1 mole of hypo solution is present in 1 liter of solution
So, the number of moles of hypo solution used = 0.1 x 0.12 L = 0.012 moles
From the balanced chemical equation, it is clear that 1 mole of iodine is required for the titration of 1 mole of CO
Therefore, the number of moles of CO produced = 0.012 moles
3. Calculation of moles of carbon converted into CO:
From the balanced chemical equation, it is clear that 2 moles of CO are produced from 2 moles of carbon
Therefore, the number of moles of carbon converted into CO = 0.012 x 2 = 0.024 moles
4. Calculation of percentage of carbon converted into CO:
The initial amount of carbon burnt completely = 1.2 gm = 1.2/12 = 0.1 moles (since the atomic mass of carbon is 12)
Therefore, the percentage of carbon converted into CO = (0.024/0.1) x 100 = 24%
However, the question asks for the percentage of carbon converted into CO and not the percentage of CO produced from carbon
From the balanced chemical equation, it is clear that 1 mole of CO is produced from 1 mole of carbon
Therefore, the percentage of carbon converted into CO = 24 x 1 = 24%
Hence, the correct answer is option D (70%).
- Amount of carbon burnt completely = 1.2 gm
- Gases produced = CO and CO2
- The mixture is treated with solid 1205 to know the amount of CO produced
- The liberated iodine required 120 ml of 0.1 M hypo solution for complete titration
To find: The percentage of carbon converted into CO
Solution:
1. Balanced chemical equation for the combustion of carbon:
C + O2 -> CO2
2C + O2 -> 2CO (since both CO and CO2 are produced, it means that there was a limited supply of oxygen)
2. Calculation of moles of iodine used in the titration:
0.1 M hypo solution means that 0.1 mole of hypo solution is present in 1 liter of solution
So, the number of moles of hypo solution used = 0.1 x 0.12 L = 0.012 moles
From the balanced chemical equation, it is clear that 1 mole of iodine is required for the titration of 1 mole of CO
Therefore, the number of moles of CO produced = 0.012 moles
3. Calculation of moles of carbon converted into CO:
From the balanced chemical equation, it is clear that 2 moles of CO are produced from 2 moles of carbon
Therefore, the number of moles of carbon converted into CO = 0.012 x 2 = 0.024 moles
4. Calculation of percentage of carbon converted into CO:
The initial amount of carbon burnt completely = 1.2 gm = 1.2/12 = 0.1 moles (since the atomic mass of carbon is 12)
Therefore, the percentage of carbon converted into CO = (0.024/0.1) x 100 = 24%
However, the question asks for the percentage of carbon converted into CO and not the percentage of CO produced from carbon
From the balanced chemical equation, it is clear that 1 mole of CO is produced from 1 mole of carbon
Therefore, the percentage of carbon converted into CO = 24 x 1 = 24%
Hence, the correct answer is option D (70%).
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1.2 gm of carbon is burnt completely in oxygen (limited supply) to produce CO and C02. This mixture of gases is treated with solid 1205 (to know the amount of CO produced), the liberated iodine required 120 ml of 0.1 M hypo solution for complete titration. The % of carbon converted into CO is :a)60%b)100%c)50%d)70%Correct answer is option 'D'. Can you explain this answer?
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1.2 gm of carbon is burnt completely in oxygen (limited supply) to produce CO and C02. This mixture of gases is treated with solid 1205 (to know the amount of CO produced), the liberated iodine required 120 ml of 0.1 M hypo solution for complete titration. The % of carbon converted into CO is :a)60%b)100%c)50%d)70%Correct answer is option 'D'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about 1.2 gm of carbon is burnt completely in oxygen (limited supply) to produce CO and C02. This mixture of gases is treated with solid 1205 (to know the amount of CO produced), the liberated iodine required 120 ml of 0.1 M hypo solution for complete titration. The % of carbon converted into CO is :a)60%b)100%c)50%d)70%Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 1.2 gm of carbon is burnt completely in oxygen (limited supply) to produce CO and C02. This mixture of gases is treated with solid 1205 (to know the amount of CO produced), the liberated iodine required 120 ml of 0.1 M hypo solution for complete titration. The % of carbon converted into CO is :a)60%b)100%c)50%d)70%Correct answer is option 'D'. Can you explain this answer?.
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