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A6 CM tall object is placed perpendicular to the principal axis of a concave mirror of focal length 12 CM the distance of the objective from the pole of a mirror is 16 cm use mirror formula to find the position nature and the size of the image of formed?
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A6 CM tall object is placed perpendicular to the principal axis of a c...
Given Data
- Height of the object (h) = 6 cm
- Focal length of the concave mirror (f) = -12 cm (concave mirrors have negative focal lengths)
- Distance of the object from the mirror (u) = -16 cm (object distance is negative in mirror formula)
Mirror Formula
The mirror formula is given by:
1/f = 1/v + 1/u
Where:
- f = focal length
- v = image distance
- u = object distance
Calculating Image Distance (v)
- Plugging the values into the mirror formula:
1/-12 = 1/v + 1/-16
- Rearranging gives:
1/v = 1/-12 + 1/16
- Finding a common denominator (48):
1/v = -4/48 + 3/48
1/v = -1/48
- Thus, v = -48 cm
Position of the Image
- The negative sign indicates that the image is formed on the same side as the object.
Nature of the Image
- Since the image distance (v) is negative and the object is placed before the mirror, the image is:
- Real
- Inverted
Calculating Size of the Image (h')
- The magnification (m) is given by the formula:
m = h'/h = -v/u
- Plugging in the values:
m = -(-48)/(-16) = 3
- Thus, h' = m * h = 3 * 6 = 18 cm
Final Summary
- Position of the Image: 48 cm in front of the mirror
- Nature of the Image: Real and inverted
- Size of the Image: 18 cm
This detailed analysis shows how a concave mirror forms an image of an object placed in front of it, using the mirror formula effectively.
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A6 CM tall object is placed perpendicular to the principal axis of a concave mirror of focal length 12 CM the distance of the objective from the pole of a mirror is 16 cm use mirror formula to find the position nature and the size of the image of formed?
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