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Find at the variance given that the Arithmetic Mean = ( 8 + 4)/2
- a)2
- b)6
- c)1
- d)4
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Find at the variance given that the Arithmetic Mean = ( 8 + 4)/2a)2b)6...
We know that S. D = range/2
= Max-min/2
=8-4/2=2
And variance = (sd)2
= 22= 4
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Find at the variance given that the Arithmetic Mean = ( 8 + 4)/2a)2b)6...
Given that Arithmetic Mean = (8+4)/2 = 6
To find the variance, we need to first find the deviations of each number from the mean.
Deviation of 8 from mean = 8 - 6 = 2
Deviation of 4 from mean = 4 - 6 = -2
We square each deviation to get the squared deviations.
Squared deviation of 2 = 2^2 = 4
Squared deviation of -2 = (-2)^2 = 4
We then find the average of the squared deviations, which is the variance.
Variance = (4 + 4)/2 = 4
Therefore, the correct answer is option D) 4.
To find the variance, we need to first find the deviations of each number from the mean.
Deviation of 8 from mean = 8 - 6 = 2
Deviation of 4 from mean = 4 - 6 = -2
We square each deviation to get the squared deviations.
Squared deviation of 2 = 2^2 = 4
Squared deviation of -2 = (-2)^2 = 4
We then find the average of the squared deviations, which is the variance.
Variance = (4 + 4)/2 = 4
Therefore, the correct answer is option D) 4.
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Find at the variance given that the Arithmetic Mean = ( 8 + 4)/2a)2b)6c)1d)4Correct answer is option 'D'. Can you explain this answer?
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