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The dimensions of  permittivity of free spaceand E = electric field) are :
  • a)
    [MLT-1]
  • b)
    [ML2T-2]
  • c)
    [ML-1T-2]
  • d)
    [ML2T-1]
Correct answer is option 'C'. Can you explain this answer?
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The dimensions of permittivity of free spaceand E = electric field) ar...
C
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Can you explain the answer of this question below:A dense collection of equal number of electrons and positive ions is called neutral plasma. Certain solids containing fixed positive ions surrounded by free electrons can be treated as neutral plasma. Let N be the number density of free electrons, each of mass m. When the electrons are subjected to an electric field, they are displaced relatively away from the heavy positive ions. If the electric field becomes zero, the electrons begin to oscillate about the positive ions with a natural angular frequency wP which is called the plasma frequency. To sustain the oscillations, a time varying electric field needs to be applied that has an angular frequency w, where a part of the energy is absorbed and a part of it is reflected. As w approaches wP, all the free electrons are set to resonance together and all the energy is reflected. This is the explanation of high reflectivity of metals.Taking the electronic charge as e and the permittivity as 0, use dimensional analysis to determine the correct expression for wP. [JEE-2011]A:B:C:D:The answer is C.

A dense collection of equal number of electrons and positive ions is called neutral plasma. Certain solids containing fixed positive ions surrounded by free electrons can be treated as neutral plasma. Let N be the number density of free electrons, each of mass m. When the electrons are subjected to an electric field, they are displaced relatively away from the heavy positive ions. If the electric field becomes zero, the electrons begin to oscillate about the positive ions with a natural angular frequency wP which is called the plasma frequency. To sustain the oscillations, a time varying electric field needs to be applied that has an angular frequency w, where a part of the energy is absorbed and a part of it is reflected. As w approaches wP, all the free electrons are set to resonance together and all the energy is reflected. This is the explanation of high reflectivity of metals.Taking the electronic charge as e and the permittivity as ε0, use dimensional analysis to determine the correct expression for wP.

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The dimensions of permittivity of free spaceand E = electric field) are :a)[MLT-1]b)[ML2T-2]c)[ML-1T-2]d)[ML2T-1]Correct answer is option 'C'. Can you explain this answer?
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The dimensions of permittivity of free spaceand E = electric field) are :a)[MLT-1]b)[ML2T-2]c)[ML-1T-2]d)[ML2T-1]Correct answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The dimensions of permittivity of free spaceand E = electric field) are :a)[MLT-1]b)[ML2T-2]c)[ML-1T-2]d)[ML2T-1]Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The dimensions of permittivity of free spaceand E = electric field) are :a)[MLT-1]b)[ML2T-2]c)[ML-1T-2]d)[ML2T-1]Correct answer is option 'C'. Can you explain this answer?.
Solutions for The dimensions of permittivity of free spaceand E = electric field) are :a)[MLT-1]b)[ML2T-2]c)[ML-1T-2]d)[ML2T-1]Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11. Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
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