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The power consumed by a coil is 300 W when connected to 30 V dc source and 108 W. When connected to a 30 V A.C. source. The reactance of the coil is
- a)3 ?
- b)4 ?
- c)5 ?
- d)6.67 ?
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
The power consumed by a coil is300 W when connected to 30 V dcsource a...
P = 300W, V = 30V(DC)
I2 R = 300
I2 R = 300
Most Upvoted Answer
The power consumed by a coil is300 W when connected to 30 V dcsource a...
To find the reactance of the coil, we can use the formula:
Power = Voltage^2 / Reactance
For the DC source:
300 W = (30 V)^2 / Reactance
Simplifying, we get:
300 W * Reactance = (30 V)^2
300 W * Reactance = 900 V^2
Reactance = 900 V^2 / 300 W
Reactance = 3 Ω
For the AC source:
108 W = (30 V)^2 / Reactance
Simplifying, we get:
108 W * Reactance = (30 V)^2
108 W * Reactance = 900 V^2
Reactance = 900 V^2 / 108 W
Reactance = 8.33 Ω
Therefore, the reactance of the coil is 3 Ω for the DC source and approximately 8.33 Ω for the AC source.
Power = Voltage^2 / Reactance
For the DC source:
300 W = (30 V)^2 / Reactance
Simplifying, we get:
300 W * Reactance = (30 V)^2
300 W * Reactance = 900 V^2
Reactance = 900 V^2 / 300 W
Reactance = 3 Ω
For the AC source:
108 W = (30 V)^2 / Reactance
Simplifying, we get:
108 W * Reactance = (30 V)^2
108 W * Reactance = 900 V^2
Reactance = 900 V^2 / 108 W
Reactance = 8.33 Ω
Therefore, the reactance of the coil is 3 Ω for the DC source and approximately 8.33 Ω for the AC source.
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The power consumed by a coil is300 W when connected to 30 V dcsource and 108 W. When connectedto a 30 V A.C. source. The reactanceof the coil isa)3 ?b)4 ?c)5 ?d)6.67 ?Correct answer is option 'B'. Can you explain this answer?
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