Chemistry Exam > Chemistry Questions > In a zero-order reaction for every 10° ri...
Start Learning for Free
In a zero-order reaction for every 10° rise of temperature, the rate is doubled. If the temperature is increased from 10°C to 100°C, the rate of the reaction will become
- a)64 times
- b)128 times
- c)256 times
- d)512 times
Correct answer is option 'D'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
In a zero-order reaction for every 10° rise of temperature, the ra...
For 10^o rise in temperature, n = 1
so rate = 2^n = 2^1 = 2
When temperature is increased from 10^o C to 100^o C change in temperature = 100 -10 = 90^oC i.e n=9 so, rate = 29 = 512 times.
Alternate method: With every 10^o C rise in temperature, rate becomes double, so
r^r/r = 2 (100 - 10 /10) = 2^9 = 512 times
Most Upvoted Answer
In a zero-order reaction for every 10° rise of temperature, the ra...
% decrease in concentration of the reactant, the rate of reaction decreases by 10%. This means that the rate of reaction is independent of the concentration of the reactant and remains constant throughout the reaction.
Mathematically, the zero-order rate equation can be expressed as:
rate = k
where k is the rate constant. The integrated form of the zero-order rate equation is:
[A]t = -kt + [A]0
where [A]t is the concentration of the reactant at time t, [A]0 is the initial concentration of the reactant, and k is the rate constant.
In a zero-order reaction, the half-life of the reaction is directly proportional to the initial concentration of the reactant. The half-life can be calculated using the following equation:
t1/2 = [A]0 / 2k
where t1/2 is the half-life of the reaction, and [A]0 is the initial concentration of the reactant.
Examples of zero-order reactions include the decomposition of hydrogen peroxide catalyzed by potassium permanganate and the oxidation of ethanol catalyzed by copper.
Mathematically, the zero-order rate equation can be expressed as:
rate = k
where k is the rate constant. The integrated form of the zero-order rate equation is:
[A]t = -kt + [A]0
where [A]t is the concentration of the reactant at time t, [A]0 is the initial concentration of the reactant, and k is the rate constant.
In a zero-order reaction, the half-life of the reaction is directly proportional to the initial concentration of the reactant. The half-life can be calculated using the following equation:
t1/2 = [A]0 / 2k
where t1/2 is the half-life of the reaction, and [A]0 is the initial concentration of the reactant.
Examples of zero-order reactions include the decomposition of hydrogen peroxide catalyzed by potassium permanganate and the oxidation of ethanol catalyzed by copper.
Free Test
FREE
| Start Free Test |
Community Answer
In a zero-order reaction for every 10° rise of temperature, the ra...
For 1st 10C reaction is 1time then total step of 10C increase upto 100 =(100 - 1)/10 = 10 since in 2nd step it is 2^1 so with starting 2nd step to last step it will be =2^(10 -1) =2^9=512 (ans)
|
Explore Courses for Chemistry exam
|
|
Similar Chemistry Doubts
In a zero-order reaction for every 10° rise of temperature, the rate is doubled. If the temperature is increased from 10°C to 100°C, the rate of the reaction will becomea)64 timesb)128 timesc)256 timesd)512 timesCorrect answer is option 'D'. Can you explain this answer?
Question Description
In a zero-order reaction for every 10° rise of temperature, the rate is doubled. If the temperature is increased from 10°C to 100°C, the rate of the reaction will becomea)64 timesb)128 timesc)256 timesd)512 timesCorrect answer is option 'D'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about In a zero-order reaction for every 10° rise of temperature, the rate is doubled. If the temperature is increased from 10°C to 100°C, the rate of the reaction will becomea)64 timesb)128 timesc)256 timesd)512 timesCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a zero-order reaction for every 10° rise of temperature, the rate is doubled. If the temperature is increased from 10°C to 100°C, the rate of the reaction will becomea)64 timesb)128 timesc)256 timesd)512 timesCorrect answer is option 'D'. Can you explain this answer?.
In a zero-order reaction for every 10° rise of temperature, the rate is doubled. If the temperature is increased from 10°C to 100°C, the rate of the reaction will becomea)64 timesb)128 timesc)256 timesd)512 timesCorrect answer is option 'D'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about In a zero-order reaction for every 10° rise of temperature, the rate is doubled. If the temperature is increased from 10°C to 100°C, the rate of the reaction will becomea)64 timesb)128 timesc)256 timesd)512 timesCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a zero-order reaction for every 10° rise of temperature, the rate is doubled. If the temperature is increased from 10°C to 100°C, the rate of the reaction will becomea)64 timesb)128 timesc)256 timesd)512 timesCorrect answer is option 'D'. Can you explain this answer?.
Solutions for In a zero-order reaction for every 10° rise of temperature, the rate is doubled. If the temperature is increased from 10°C to 100°C, the rate of the reaction will becomea)64 timesb)128 timesc)256 timesd)512 timesCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
Download more important topics, notes, lectures and mock test series for Chemistry Exam by signing up for free.
Here you can find the meaning of In a zero-order reaction for every 10° rise of temperature, the rate is doubled. If the temperature is increased from 10°C to 100°C, the rate of the reaction will becomea)64 timesb)128 timesc)256 timesd)512 timesCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
In a zero-order reaction for every 10° rise of temperature, the rate is doubled. If the temperature is increased from 10°C to 100°C, the rate of the reaction will becomea)64 timesb)128 timesc)256 timesd)512 timesCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for In a zero-order reaction for every 10° rise of temperature, the rate is doubled. If the temperature is increased from 10°C to 100°C, the rate of the reaction will becomea)64 timesb)128 timesc)256 timesd)512 timesCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of In a zero-order reaction for every 10° rise of temperature, the rate is doubled. If the temperature is increased from 10°C to 100°C, the rate of the reaction will becomea)64 timesb)128 timesc)256 timesd)512 timesCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice In a zero-order reaction for every 10° rise of temperature, the rate is doubled. If the temperature is increased from 10°C to 100°C, the rate of the reaction will becomea)64 timesb)128 timesc)256 timesd)512 timesCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice Chemistry tests.
|
|
Explore Courses for Chemistry exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup