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The de – Broglie wavelength of an electron is 600 nm. The velocity of the electron having the mass 9.1 X 10-31 Kg is
  • a)
    0.0012 x 10+4 m/s
  • b)
    0.0012 x 10+3 m/s
  • c)
    0.0012 x 10+6 m/s
  • d)
    0.0012 x 10+2 m/s
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The de – Broglie wavelength of an electron is 600 nm. The veloci...
1nm= 10^-9m.
wavelength= 600nm= 600 ×10-9m
wavelength= h/p.
wavelength= h/mv
v= h/ m wavelength
v=6.625×10^-34/9.1×10^-31×600× 10-9.
v= 6.625 × 10+4/9.1 ×6.
v= 6.625× 10+4/9.1×6.
v= 6.625 ×104/54.6.
v= 0.12 × 104.
v= 0.0012 × 10+6 .
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Most Upvoted Answer
The de – Broglie wavelength of an electron is 600 nm. The veloci...
1nm= 10^-9m.wavelength= 600nm= 600 ×10-9mwavelength= h/p.wavelength= h/mvv= h/ m wavelengthv=6.625×10^-34/9.1×10^-31×600× 10^-9.v= 6.625 × 10^+4/9.1 ×6.v= 6.625× 10 ^+4/9.1×6.v= 6.625 ×10^4/54.6.v= 0.12 × 10^4.v= 0.0012 × 10^6 .
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Community Answer
The de – Broglie wavelength of an electron is 600 nm. The veloci...
Lambda is equal to h/mv.change the eqn as v - h/m lambda.then applying the values. we get the answer.
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The de – Broglie wavelength of an electron is 600 nm. The velocity of the electron having the mass 9.1 X 10-31Kg isa)0.0012 x 10+4m/sb)0.0012 x 10+3m/sc)0.0012 x 10+6m/sd)0.0012 x 10+2m/sCorrect answer is option 'C'. Can you explain this answer?
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The de – Broglie wavelength of an electron is 600 nm. The velocity of the electron having the mass 9.1 X 10-31Kg isa)0.0012 x 10+4m/sb)0.0012 x 10+3m/sc)0.0012 x 10+6m/sd)0.0012 x 10+2m/sCorrect answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The de – Broglie wavelength of an electron is 600 nm. The velocity of the electron having the mass 9.1 X 10-31Kg isa)0.0012 x 10+4m/sb)0.0012 x 10+3m/sc)0.0012 x 10+6m/sd)0.0012 x 10+2m/sCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The de – Broglie wavelength of an electron is 600 nm. The velocity of the electron having the mass 9.1 X 10-31Kg isa)0.0012 x 10+4m/sb)0.0012 x 10+3m/sc)0.0012 x 10+6m/sd)0.0012 x 10+2m/sCorrect answer is option 'C'. Can you explain this answer?.
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