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The de Broglie wavelength of an electron is 8.7 x 10-11 m. The mass of an electron is 9.1 x 10-31 kg. The velocity of this electron is:
- a)0.0837 × 108 m/s
- b)6.9 × 10-5 m/s
- c)8.4 × 103 m/s
- d)1.2 × 10-7 m/s
Correct answer is option 'A'. Can you explain this answer?
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The de Broglie wavelength of an electron is 8.7 x 10-11m. The mass of ...
Wavelength = h/p = h/ mv.
v= h/ m.wavelength
v= 6.625 × 10-34/9.1×10-31 × 8.7 × 10-11
v= 6.625 × 108/ 9.1× 8.7
v= 0.08367 ×108.
v= h/ m.wavelength
v= 6.625 × 10-34/9.1×10-31 × 8.7 × 10-11
v= 6.625 × 108/ 9.1× 8.7
v= 0.08367 ×108.
Most Upvoted Answer
The de Broglie wavelength of an electron is 8.7 x 10-11m. The mass of ...
Wavelength = h/p = h/ mv.v= h/ m.wavelengthv= 6.625 × 10^ -34/9.1×10^-31 × 8.7 × 10^ -11v= 6.625 × 10^8/ 9.1× 8.7v= 0.08367 ×10 ^ 8
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The de Broglie wavelength of an electron is 8.7 x 10-11m. The mass of ...
Given:
- de Broglie wavelength (λ) = 8.7 x 10^(-11) m
- Mass of an electron (m) = 9.1 x 10^(-31) kg
Formula:
The de Broglie wavelength of a particle is given by the equation:
λ = h / p
Where:
- λ is the de Broglie wavelength
- h is the Planck's constant (6.626 x 10^(-34) J·s)
- p is the momentum of the particle
Step 1: Calculate the momentum of the electron
Using the given de Broglie wavelength and the formula above, we can rearrange the equation to solve for momentum:
p = h / λ
Substituting the given values:
p = (6.626 x 10^(-34) J·s) / (8.7 x 10^(-11) m)
Simplifying:
p = 7.6 x 10^(-24) kg·m/s
Step 2: Calculate the velocity of the electron
The momentum of an object is given by the equation:
p = m * v
Where:
- p is the momentum
- m is the mass of the object
- v is the velocity of the object
We can rearrange the equation to solve for velocity:
v = p / m
Substituting the given values:
v = (7.6 x 10^(-24) kg·m/s) / (9.1 x 10^(-31) kg)
Simplifying:
v = 8.4 x 10^7 m/s
Step 3: Convert velocity to scientific notation
The velocity of the electron is 8.4 x 10^7 m/s. This can be written in scientific notation as:
8.4 x 10^7 m/s = 0.084 x 10^8 m/s
Conclusion:
The velocity of the electron is 0.084 x 10^8 m/s, which is approximately equal to 0.0837 x 10^8 m/s. Therefore, the correct answer is option A) 0.0837 x 10^8 m/s.
- de Broglie wavelength (λ) = 8.7 x 10^(-11) m
- Mass of an electron (m) = 9.1 x 10^(-31) kg
Formula:
The de Broglie wavelength of a particle is given by the equation:
λ = h / p
Where:
- λ is the de Broglie wavelength
- h is the Planck's constant (6.626 x 10^(-34) J·s)
- p is the momentum of the particle
Step 1: Calculate the momentum of the electron
Using the given de Broglie wavelength and the formula above, we can rearrange the equation to solve for momentum:
p = h / λ
Substituting the given values:
p = (6.626 x 10^(-34) J·s) / (8.7 x 10^(-11) m)
Simplifying:
p = 7.6 x 10^(-24) kg·m/s
Step 2: Calculate the velocity of the electron
The momentum of an object is given by the equation:
p = m * v
Where:
- p is the momentum
- m is the mass of the object
- v is the velocity of the object
We can rearrange the equation to solve for velocity:
v = p / m
Substituting the given values:
v = (7.6 x 10^(-24) kg·m/s) / (9.1 x 10^(-31) kg)
Simplifying:
v = 8.4 x 10^7 m/s
Step 3: Convert velocity to scientific notation
The velocity of the electron is 8.4 x 10^7 m/s. This can be written in scientific notation as:
8.4 x 10^7 m/s = 0.084 x 10^8 m/s
Conclusion:
The velocity of the electron is 0.084 x 10^8 m/s, which is approximately equal to 0.0837 x 10^8 m/s. Therefore, the correct answer is option A) 0.0837 x 10^8 m/s.
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The de Broglie wavelength of an electron is 8.7 x 10-11m. The mass of an electron is 9.1 x 10-31kg. The velocity of this electron is:a)0.0837 × 108m/sb)6.9 × 10-5m/sc)8.4 × 103m/sd)1.2 × 10-7m/sCorrect answer is option 'A'. Can you explain this answer?
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The de Broglie wavelength of an electron is 8.7 x 10-11m. The mass of an electron is 9.1 x 10-31kg. The velocity of this electron is:a)0.0837 × 108m/sb)6.9 × 10-5m/sc)8.4 × 103m/sd)1.2 × 10-7m/sCorrect answer is option 'A'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The de Broglie wavelength of an electron is 8.7 x 10-11m. The mass of an electron is 9.1 x 10-31kg. The velocity of this electron is:a)0.0837 × 108m/sb)6.9 × 10-5m/sc)8.4 × 103m/sd)1.2 × 10-7m/sCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The de Broglie wavelength of an electron is 8.7 x 10-11m. The mass of an electron is 9.1 x 10-31kg. The velocity of this electron is:a)0.0837 × 108m/sb)6.9 × 10-5m/sc)8.4 × 103m/sd)1.2 × 10-7m/sCorrect answer is option 'A'. Can you explain this answer?.
The de Broglie wavelength of an electron is 8.7 x 10-11m. The mass of an electron is 9.1 x 10-31kg. The velocity of this electron is:a)0.0837 × 108m/sb)6.9 × 10-5m/sc)8.4 × 103m/sd)1.2 × 10-7m/sCorrect answer is option 'A'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The de Broglie wavelength of an electron is 8.7 x 10-11m. The mass of an electron is 9.1 x 10-31kg. The velocity of this electron is:a)0.0837 × 108m/sb)6.9 × 10-5m/sc)8.4 × 103m/sd)1.2 × 10-7m/sCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The de Broglie wavelength of an electron is 8.7 x 10-11m. The mass of an electron is 9.1 x 10-31kg. The velocity of this electron is:a)0.0837 × 108m/sb)6.9 × 10-5m/sc)8.4 × 103m/sd)1.2 × 10-7m/sCorrect answer is option 'A'. Can you explain this answer?.
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