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A bus arrives every 10 minutes at a bus stop. Assuming waiting time X for bus is uniformly distributed, the probability that a person has to wait for the bus for more than 7 minutes is
  • a)
    0.1
  • b)
    0.7
  • c)
    0.2
  • d)
    0.3
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A bus arrives every 10 minutes at a bus stop. Assuming waiting time X ...
P (7< <10) = = 0.3 
Hint p.d.f is f(x) =
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A bus arrives every 10 minutes at a bus stop. Assuming waiting time X ...
P (7< <10) = = 0.3 
Hint p.d.f is f(x) =
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A bus arrives every 10 minutes at a bus stop. Assuming waiting time X ...
Question Analysis
The question states that a bus arrives every 10 minutes at a bus stop. The waiting time for the bus, denoted as X, is assumed to be uniformly distributed. We are asked to find the probability that a person has to wait for the bus for more than 7 minutes.

Solution
To solve this problem, we need to understand the concept of a uniform distribution and apply it to find the probability.

Uniform Distribution
In statistics, a uniform distribution is a probability distribution in which all outcomes are equally likely. In this case, the waiting time for the bus is assumed to follow a uniform distribution because the bus arrives every 10 minutes, and there is an equal likelihood of the bus arriving at any given minute within that 10-minute interval.

Finding the Probability
To find the probability that a person has to wait for the bus for more than 7 minutes, we need to calculate the area under the probability density function (PDF) curve for the waiting time X, from 7 minutes to 10 minutes.

Since the waiting time X is uniformly distributed, the PDF is a constant within the interval [0, 10] and zero outside that interval. The height of the PDF is 1/10, as the total area under the curve must be equal to 1.

Calculating the Probability
To calculate the probability, we need to find the area under the PDF curve from 7 minutes to 10 minutes. This can be done by finding the length of the interval [7, 10] and multiplying it by the height of the PDF.

Length of Interval = 10 - 7 = 3 minutes
Height of PDF = 1/10

Area under Curve = Length of Interval * Height of PDF
Area under Curve = 3 * (1/10) = 3/10

Therefore, the probability that a person has to wait for the bus for more than 7 minutes is 3/10 or 0.3.

Answer
The correct answer is option D) 0.3.
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A bus arrives every 10 minutes at a bus stop. Assuming waiting time X for bus is uniformly distributed, the probability that a person has to wait for the bus for more than 7 minutes isa)0.1b)0.7c) 0.2d)0.3Correct answer is option 'D'. Can you explain this answer?
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