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What is the maximum current that can be drawn from a cell of emf E and internal resistance r connected to an external resistance R?
- a)I = E/(R+r)
- b)infinite
- c)I = E/R
- d)I = E/r
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
What is the maximum current that can be drawn from a cell of emf E and...
as the maximum current that can be drawn from a cell is for R =0 therefore, it is I = E/r.
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What is the maximum current that can be drawn from a cell of emf E and...
Maximum Current Drawn from a Cell
The maximum current that can be drawn from a cell of emf E and internal resistance r connected to an external resistance R can be calculated using the following formula:
I = E/r
Explanation
The maximum current that can be drawn from a cell is determined by its emf and internal resistance. The internal resistance of a cell represents the opposition to the flow of current within the cell itself. The external resistance represents the opposition to the flow of current outside the cell.
When an external resistance is connected across the cell, a current flows through the external resistance and the internal resistance of the cell. The current that flows through the external resistance is given by Ohm's law:
I = E/(R+r)
where R is the external resistance and r is the internal resistance of the cell.
To find the maximum current that can be drawn from the cell, we need to minimize the value of R+r. This is because the current is inversely proportional to the total resistance in the circuit. Therefore, the maximum current is obtained when R+r is minimized, which occurs when R = 0.
Thus, the maximum current that can be drawn from the cell is given by:
I = E/r
This formula shows that the maximum current that can be drawn from a cell is directly proportional to its emf and inversely proportional to its internal resistance. Therefore, the lower the internal resistance of the cell, the higher the maximum current that can be drawn from it.
The maximum current that can be drawn from a cell of emf E and internal resistance r connected to an external resistance R can be calculated using the following formula:
I = E/r
Explanation
The maximum current that can be drawn from a cell is determined by its emf and internal resistance. The internal resistance of a cell represents the opposition to the flow of current within the cell itself. The external resistance represents the opposition to the flow of current outside the cell.
When an external resistance is connected across the cell, a current flows through the external resistance and the internal resistance of the cell. The current that flows through the external resistance is given by Ohm's law:
I = E/(R+r)
where R is the external resistance and r is the internal resistance of the cell.
To find the maximum current that can be drawn from the cell, we need to minimize the value of R+r. This is because the current is inversely proportional to the total resistance in the circuit. Therefore, the maximum current is obtained when R+r is minimized, which occurs when R = 0.
Thus, the maximum current that can be drawn from the cell is given by:
I = E/r
This formula shows that the maximum current that can be drawn from a cell is directly proportional to its emf and inversely proportional to its internal resistance. Therefore, the lower the internal resistance of the cell, the higher the maximum current that can be drawn from it.
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What is the maximum current that can be drawn from a cell of emf E and internal resistance r connected to an external resistance R?a)I = E/(R+r)b)infinitec)I = E/Rd)I = E/rCorrect answer is option 'D'. Can you explain this answer?
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