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If in a computer, 16 bits are used to specify address in a RAM, the number of addresses will be ___
- a)216
- b)65,536
- c)64K
- d)128K
- e)135K
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
If in a computer, 16 bits are used to specify address in a RAM, the nu...
Addressing in a RAM
Addressing is a process of assigning a unique identity to each memory location in a computer's Random Access Memory (RAM). The number of memory locations that can be addressed in a RAM depends on the number of bits used to specify the address.
16-bit Addressing
If a computer uses 16 bits to specify the address in a RAM, it means that each memory location can be uniquely identified by a 16-bit binary number. The total number of unique binary numbers that can be represented using 16 bits is 2^16.
Calculating the Number of Addresses
To calculate the number of addresses that can be specified using 16 bits, we need to convert 2^16 from binary to decimal.
2^16 in decimal is 65,536. Therefore, the number of addresses that can be specified using 16 bits is 65,536.
Answer
Hence, option B, 65,536 is the correct answer.
Addressing is a process of assigning a unique identity to each memory location in a computer's Random Access Memory (RAM). The number of memory locations that can be addressed in a RAM depends on the number of bits used to specify the address.
16-bit Addressing
If a computer uses 16 bits to specify the address in a RAM, it means that each memory location can be uniquely identified by a 16-bit binary number. The total number of unique binary numbers that can be represented using 16 bits is 2^16.
Calculating the Number of Addresses
To calculate the number of addresses that can be specified using 16 bits, we need to convert 2^16 from binary to decimal.
2^16 in decimal is 65,536. Therefore, the number of addresses that can be specified using 16 bits is 65,536.
Answer
Hence, option B, 65,536 is the correct answer.
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If in a computer, 16 bits are used to specify address in a RAM, the nu...
2^16=65536..... actually 16 bit pretend to 2 bytes..... which is the size of a integer data type which can store the data from address.... -32767 to 32678..... containing total 65536
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