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Work is done on a adiabatic system due to which its velocity changes from 10 m/s to 20 m/s, elevation
increases by 20 m and temperature increases by 1 K. The mass of the system is 10 kg, Cv = 100 J/(kg.K) and gravitational acceleration is 10 m/s2. If there is no change in any other component of the energy of the system, the magnitude of total work done (in kJ) on the system is
increases by 20 m and temperature increases by 1 K. The mass of the system is 10 kg, Cv = 100 J/(kg.K) and gravitational acceleration is 10 m/s2. If there is no change in any other component of the energy of the system, the magnitude of total work done (in kJ) on the system is
Correct answer is '4.5'. Can you explain this answer?
Most Upvoted Answer
Work is done on a adiabatic system due to which its velocity changes f...
Given: C1 = 10 m/s, C2 = 20 m/s, z2 – z1 = 20 m,
T2 – T1 = 1 K
CV = 100 J/kg-K, g = 10 m/s2, δQ = 0
T2 – T1 = 1 K
CV = 100 J/kg-K, g = 10 m/s2, δQ = 0
Assuming compressible fluid with γ = 1
SFEE:
On the system, δ W = 4.5 kJ
Hence, the correct answer is 4.5.
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Work is done on a adiabatic system due to which its velocity changes f...
Understanding the Problem
In an adiabatic system, work is done, resulting in changes in velocity, elevation, and temperature. We need to calculate the total work done on the system with given parameters.
Given Data
- Initial velocity (u) = 10 m/s
- Final velocity (v) = 20 m/s
- Elevation increase (h) = 20 m
- Temperature increase (ΔT) = 1 K
- Mass (m) = 10 kg
- Specific heat at constant volume (Cv) = 100 J/(kg·K)
- Gravitational acceleration (g) = 10 m/s²
Calculating Work Done
1. Change in Kinetic Energy (KE):
- KE_initial = 0.5 * m * u² = 0.5 * 10 * (10)² = 500 J
- KE_final = 0.5 * m * v² = 0.5 * 10 * (20)² = 2000 J
- Change in KE = KE_final - KE_initial = 2000 J - 500 J = 1500 J
2. Change in Potential Energy (PE):
- PE = m * g * h = 10 * 10 * 20 = 2000 J
3. Change in Internal Energy (UE):
- UE = m * Cv * ΔT = 10 * 100 * 1 = 1000 J
Total Energy Change
- Total Energy Change = Change in KE + Change in PE + Change in UE
- Total Energy Change = 1500 J + 2000 J + 1000 J = 4500 J
Calculating Total Work Done
- Since the system is adiabatic, the total work done (W) is equal to the total energy change.
- W = 4500 J = 4.5 kJ
Conclusion
The total work done on the system is 4.5 kJ, considering changes in kinetic energy, potential energy, and internal energy.
In an adiabatic system, work is done, resulting in changes in velocity, elevation, and temperature. We need to calculate the total work done on the system with given parameters.
Given Data
- Initial velocity (u) = 10 m/s
- Final velocity (v) = 20 m/s
- Elevation increase (h) = 20 m
- Temperature increase (ΔT) = 1 K
- Mass (m) = 10 kg
- Specific heat at constant volume (Cv) = 100 J/(kg·K)
- Gravitational acceleration (g) = 10 m/s²
Calculating Work Done
1. Change in Kinetic Energy (KE):
- KE_initial = 0.5 * m * u² = 0.5 * 10 * (10)² = 500 J
- KE_final = 0.5 * m * v² = 0.5 * 10 * (20)² = 2000 J
- Change in KE = KE_final - KE_initial = 2000 J - 500 J = 1500 J
2. Change in Potential Energy (PE):
- PE = m * g * h = 10 * 10 * 20 = 2000 J
3. Change in Internal Energy (UE):
- UE = m * Cv * ΔT = 10 * 100 * 1 = 1000 J
Total Energy Change
- Total Energy Change = Change in KE + Change in PE + Change in UE
- Total Energy Change = 1500 J + 2000 J + 1000 J = 4500 J
Calculating Total Work Done
- Since the system is adiabatic, the total work done (W) is equal to the total energy change.
- W = 4500 J = 4.5 kJ
Conclusion
The total work done on the system is 4.5 kJ, considering changes in kinetic energy, potential energy, and internal energy.
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Work is done on a adiabatic system due to which its velocity changes from 10 m/s to 20 m/s, elevationincreases by 20 m and temperature increases by 1 K. The mass of the system is 10 kg, Cv = 100 J/(kg.K) and gravitational acceleration is 10 m/s2. If there is no change in any other component of the energy of the system, the magnitude of total work done (in kJ) on the system isCorrect answer is '4.5'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Work is done on a adiabatic system due to which its velocity changes from 10 m/s to 20 m/s, elevationincreases by 20 m and temperature increases by 1 K. The mass of the system is 10 kg, Cv = 100 J/(kg.K) and gravitational acceleration is 10 m/s2. If there is no change in any other component of the energy of the system, the magnitude of total work done (in kJ) on the system isCorrect answer is '4.5'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Work is done on a adiabatic system due to which its velocity changes from 10 m/s to 20 m/s, elevationincreases by 20 m and temperature increases by 1 K. The mass of the system is 10 kg, Cv = 100 J/(kg.K) and gravitational acceleration is 10 m/s2. If there is no change in any other component of the energy of the system, the magnitude of total work done (in kJ) on the system isCorrect answer is '4.5'. Can you explain this answer?.
Work is done on a adiabatic system due to which its velocity changes from 10 m/s to 20 m/s, elevationincreases by 20 m and temperature increases by 1 K. The mass of the system is 10 kg, Cv = 100 J/(kg.K) and gravitational acceleration is 10 m/s2. If there is no change in any other component of the energy of the system, the magnitude of total work done (in kJ) on the system isCorrect answer is '4.5'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Work is done on a adiabatic system due to which its velocity changes from 10 m/s to 20 m/s, elevationincreases by 20 m and temperature increases by 1 K. The mass of the system is 10 kg, Cv = 100 J/(kg.K) and gravitational acceleration is 10 m/s2. If there is no change in any other component of the energy of the system, the magnitude of total work done (in kJ) on the system isCorrect answer is '4.5'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Work is done on a adiabatic system due to which its velocity changes from 10 m/s to 20 m/s, elevationincreases by 20 m and temperature increases by 1 K. The mass of the system is 10 kg, Cv = 100 J/(kg.K) and gravitational acceleration is 10 m/s2. If there is no change in any other component of the energy of the system, the magnitude of total work done (in kJ) on the system isCorrect answer is '4.5'. Can you explain this answer?.
Solutions for Work is done on a adiabatic system due to which its velocity changes from 10 m/s to 20 m/s, elevationincreases by 20 m and temperature increases by 1 K. The mass of the system is 10 kg, Cv = 100 J/(kg.K) and gravitational acceleration is 10 m/s2. If there is no change in any other component of the energy of the system, the magnitude of total work done (in kJ) on the system isCorrect answer is '4.5'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering.
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ample number of questions to practice Work is done on a adiabatic system due to which its velocity changes from 10 m/s to 20 m/s, elevationincreases by 20 m and temperature increases by 1 K. The mass of the system is 10 kg, Cv = 100 J/(kg.K) and gravitational acceleration is 10 m/s2. If there is no change in any other component of the energy of the system, the magnitude of total work done (in kJ) on the system isCorrect answer is '4.5'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.
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