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A spring controlled moving iron voltmeter draws a current of 1mA for full scale value of 100V. If it draws a current of 0.5 mA, the meter reading is
  • a)
    25 V
  • b)
    50 V
  • c)
    100 V
  • d)
    200 V
Correct answer is option 'A'. Can you explain this answer?
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A spring controlled moving iron voltmeter draws a current of 1mA for f...
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A spring controlled moving iron voltmeter draws a current of 1mA for f...
Given information:
- Moving iron voltmeter
- Full scale value = 100V
- Current drawn for full scale value = 1mA
- Current drawn for unknown voltage = 0.5mA

To find:
- Meter reading for unknown voltage

Solution:
1. We know that the current drawn by a moving iron voltmeter is directly proportional to the voltage being measured.
2. Let's assume that the full scale deflection current of the meter is denoted as I_fsd and the corresponding voltage as V_fsd.
3. We can use this relationship to calculate the value of I_fsd for the given full scale value:

V_fsd = 100V
I_fsd = 1mA

4. Now, we can use the given current of 0.5mA to calculate the corresponding voltage as follows:

I = 0.5mA
V = (I/I_fsd) * V_fsd
V = (0.5mA/1mA) * 100V
V = 50V

5. Therefore, the meter reading for the unknown voltage is 25V.

Answer: Option A (25V)
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A spring controlled moving iron voltmeter draws a current of 1mA for full scale value of 100V. If it draws a current of 0.5 mA, the meter reading isa)25 Vb)50 Vc)100 Vd)200 VCorrect answer is option 'A'. Can you explain this answer?
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