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Work done in carrying 2C charge in a circular path of radius 2m around a charge of 10C is​
  • a)
    6.67J
  • b)
    60J
  • c)
    Zero
  • d)
    15J
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Work done in carrying 2C charge in a circular path of radius 2m around...
The overall work performed in carrying a 2coulomb charge in a circular orbit of radius 3 m around a charge of 10 coulomb is calculated below.
It is a well-known fact that W=qdv.
Here dV is the change in overall potential. In the circular orbit of r potential at each point is similar.
Most significantly, the value of r is 3.  
The value of dv=0 and hence W=q0=0.
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Community Answer
Work done in carrying 2C charge in a circular path of radius 2m around...
Explanation:

Given: Charge of the particle, q = 10C, Charge moved, q' = 2C, radius of the circular path, r = 2m

We need to find the work done in carrying the charge around the circular path.

Formula:

The work done in moving a charge q' from point A to point B in an electric field created by a charge q is given by:

W = qV

where V is the potential difference between the two points A and B.

For a point charge q, the electric potential at a distance r from it is given by:

V = kq/r

where k is the Coulomb constant (9 x 10^9 Nm^2/C^2).

Calculation:

The charge q exerts an electric field on the charge q' which is given by:

E = kq/r^2

The potential difference between the starting and ending points of the circular path is zero, since the electric potential depends only on the distance from the charge, and the starting and ending points have the same distance from the charge.

Therefore, the work done in carrying the charge around the circular path is zero.

Answer: (c) Zero.
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