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A dc shunt generator when driven without connecting field winding shows an open circuit terminal voltage of 12V. When field winding is connected and excited the terminal voltage drop to zero because
  • a)
    field resistance is higher than critical resistance
  • b)
    there is no residual magnetism in the field circuit
  • c)
    field winding has got wrongly connected
  • d)
    there is a fault in armature circuit
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A dc shunt generator when driven without connecting field winding show...
If shunt field resistance is more than the critical field resistance, there will be no voltage buildup beyond residual voltage but voltage would not be zero
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A dc shunt generator when driven without connecting field winding show...

Explanation:

When a DC shunt generator is driven without connecting the field winding, it means that the field winding is not excited and there is no magnetic field produced. In this case, the generator behaves like a simple permanent magnet generator with a residual magnetism. The open circuit terminal voltage, in this case, is 12V.

When the field winding is connected and excited, it creates a magnetic field in the generator. This magnetic field interacts with the armature conductors and induces a voltage in them, which is the generator's output voltage.

However, in the given scenario, when the field winding is connected and excited, the terminal voltage drops to zero. This can happen due to various reasons, but the correct answer is option 'C', which states that the field winding has got wrongly connected.

Reasons for the terminal voltage drop:

1. Wrong connection of field winding: If the field winding is not connected properly or if it is connected in reverse polarity, it can cause the terminal voltage to drop to zero. This is because the magnetic field produced by the field winding will be in the opposite direction, canceling out the magnetic field produced by the armature conductors.

2. Short circuit in the field winding: If there is a short circuit in the field winding, it can cause the terminal voltage to drop to zero. This is because the short circuit provides a low resistance path for the current, bypassing the field winding and preventing the production of a magnetic field.

3. Open circuit in the field winding: If there is an open circuit in the field winding, it can also cause the terminal voltage to drop to zero. In this case, no current flows through the field winding, and thus no magnetic field is produced.

4. Fault in the armature circuit: While this is not the correct answer in this case, a fault in the armature circuit such as a short circuit or an open circuit can also cause the terminal voltage to drop to zero. This is because the fault disrupts the flow of current in the armature conductors, affecting the generation of the output voltage.

Therefore, in the given scenario, the most likely reason for the terminal voltage to drop to zero when the field winding is connected and excited is that the field winding has got wrongly connected.
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A dc shunt generator when driven without connecting field winding shows an open circuit terminal voltage of 12V. When field winding is connected and excited the terminal voltage drop to zero becausea)field resistance is higher than critical resistanceb)there is no residual magnetism in the field circuitc)field winding has got wrongly connectedd)there is a fault in armature circuitCorrect answer is option 'C'. Can you explain this answer?
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A dc shunt generator when driven without connecting field winding shows an open circuit terminal voltage of 12V. When field winding is connected and excited the terminal voltage drop to zero becausea)field resistance is higher than critical resistanceb)there is no residual magnetism in the field circuitc)field winding has got wrongly connectedd)there is a fault in armature circuitCorrect answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A dc shunt generator when driven without connecting field winding shows an open circuit terminal voltage of 12V. When field winding is connected and excited the terminal voltage drop to zero becausea)field resistance is higher than critical resistanceb)there is no residual magnetism in the field circuitc)field winding has got wrongly connectedd)there is a fault in armature circuitCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A dc shunt generator when driven without connecting field winding shows an open circuit terminal voltage of 12V. When field winding is connected and excited the terminal voltage drop to zero becausea)field resistance is higher than critical resistanceb)there is no residual magnetism in the field circuitc)field winding has got wrongly connectedd)there is a fault in armature circuitCorrect answer is option 'C'. Can you explain this answer?.
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