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What happens to K.E. of a body when 3/4 th of mass is removed and its velocity is doubled?
- a)becomes 4 times
- b)becomes 1/2 times
- c)no change
- d)becomes 1/4 times
Correct answer is option 'B'. Can you explain this answer?
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What happens to K.E. of a body when 3/4 th of mass is removed and its ...
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What happens to K.E. of a body when 3/4 th of mass is removed and its ...
This is as k e=1/2mv^2
1/2*m/4*2 v^2
so answer is 1/2 mv^2.....
1/2*m/4*2 v^2
so answer is 1/2 mv^2.....
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What happens to K.E. of a body when 3/4 th of mass is removed and its ...
Let the mass=m
here, 3/4 of the mass is removed
then, m-3/4m=m/4
and velocity=2v
kinetic energy=1/2×mv^2
=1/2×m/4×(2v^2)
=1/2×m/4×4v^2
=1/2mv^2
so, answer will be option B.
here, 3/4 of the mass is removed
then, m-3/4m=m/4
and velocity=2v
kinetic energy=1/2×mv^2
=1/2×m/4×(2v^2)
=1/2×m/4×4v^2
=1/2mv^2
so, answer will be option B.
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What happens to K.E. of a body when 3/4 th of mass is removed and its velocity is doubled?a)becomes 4 timesb)becomes 1/2 timesc)no changed)becomes 1/4 timesCorrect answer is option 'B'. Can you explain this answer?
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