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Two slabs A and B of different materials but of the same thickness are joined end to end to form a composite slab. The thermal conductivities of A and B are K1 and K2 respectively. A steady temperature difference of 12°C is maintained across the composite slab. If K1 = K2 / 2 the temperature difference across slabs A is
  • a)
    4°C
  • b)
    6°C
  • c)
    8°C
  • d)
    10°C
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Two slabs A and B of different materials but of the same thickness are...
K×∆t =constant let k1 = 1 &k2= 2 then 1(12-t)=2(t-
0) t=4 then ∆t across A is 12-4=8Degree C.
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Two slabs A and B of different materials but of the same thickness are joined end to end to form a composite slab. The thermal conductivities of A and B are K1and K2 respectively. A steady temperature difference of 12°C is maintained across the composite slab. If K1= K2/ 2 the temperature difference across slabs A isa)4°Cb)6°Cc)8°Cd)10°CCorrect answer is option 'C'. Can you explain this answer?
Question Description
Two slabs A and B of different materials but of the same thickness are joined end to end to form a composite slab. The thermal conductivities of A and B are K1and K2 respectively. A steady temperature difference of 12°C is maintained across the composite slab. If K1= K2/ 2 the temperature difference across slabs A isa)4°Cb)6°Cc)8°Cd)10°CCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two slabs A and B of different materials but of the same thickness are joined end to end to form a composite slab. The thermal conductivities of A and B are K1and K2 respectively. A steady temperature difference of 12°C is maintained across the composite slab. If K1= K2/ 2 the temperature difference across slabs A isa)4°Cb)6°Cc)8°Cd)10°CCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two slabs A and B of different materials but of the same thickness are joined end to end to form a composite slab. The thermal conductivities of A and B are K1and K2 respectively. A steady temperature difference of 12°C is maintained across the composite slab. If K1= K2/ 2 the temperature difference across slabs A isa)4°Cb)6°Cc)8°Cd)10°CCorrect answer is option 'C'. Can you explain this answer?.
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