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Consider a compound slab consisting of two different materials having equal thickness and thermal conductivities K and 2K respectively. The equivalent thermal conductivity of the slab is
  • a)
    3K
  • b)
    4/3 K
  • c)
    2/3 K
  • d)
    none of these
Correct answer is option 'B'. Can you explain this answer?
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Solution:

To find the equivalent thermal conductivity of the slab, we can use the formula:

K_eq = (K_1 + K_2) / 2

where K_1 and K_2 are the thermal conductivities of the two materials.

In this case, we have two materials with thermal conductivities K and 2K, and they have equal thickness. So, we can use the formula as:

K_eq = (K + 2K) / 2

K_eq = 3K / 2

Therefore, the equivalent thermal conductivity of the slab is 4/3K. Hence, option (B) is the correct answer.
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Consider a compound slab consisting of two different materials having equal thickness and thermal conductivities K and 2K respectively. The equivalent thermal conductivity of the slab isa)3Kb)4/3 Kc)2/3 Kd)none of theseCorrect answer is option 'B'. Can you explain this answer?
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