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An electron in H-atom in its ground state absorbs 1.5 times as much as energy as the minimum required for its escape from the atom
Q. Thus, kinetic energy given to the emitted electron is
  • a)
    20.4 eV
  • b)
    34.0 eV
  • c)
    -20.4 eV
  • d)
    -34.0 eV
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
An electron in H-atom in its ground state absorbs 1.5 times as much as...
E1 = Energy of H-atom in the ground state = 13.6 eV 

Energy absorbed = (13.6 x 1.5) = 20.4 eV
E2 = Energy of the excited state
= 13.6+ 20.4= 34.0 eV
ΔE = KE = (E2 - E1)
= 34.0 - 13.6 = 20.4 eV
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