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If Δ0 is the octahedral splitting energy and P is the electron pairing energy, then the crystal-field stabilization energy [CFSE) of [Co(NH3)6]2+ is:
- a)–0.8Δ0 + 2P
- b)–0.8Δ0 + 1P
- c)–0.8Δ0
- d)–1.8Δ0 + 3P
Correct answer is option 'C'. Can you explain this answer?
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If Δ0 is the octahedral splitting energy and P is the electron p...
You are referring to the word "if," it is a conjunction used to introduce a condition or supposition. It is often used to express possibilities, hypothetical situations, or uncertain outcomes.
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If Δ0 is the octahedral splitting energy and P is the electron p...
It is a high spin complex with cobalt in its +2 oxidation state .d block metals when form the complex its d orbitals splits in to two energy levels(is.,t2g and eg) .here t2g levels having 5 electrons with contribution of -0.4 value per electron. and eg levels having 2 electrons with 0.6 value per electron. t2g+eg=CFSE ( 5*-0.4) +(2*0.6)= -0.8
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If Δ0 is the octahedral splitting energy and P is the electron pairing energy, then the crystal-field stabilization energy [CFSE) of [Co(NH3)6]2+ is:a)–0.8Δ0 + 2Pb)–0.8Δ0 + 1Pc)–0.8Δ0d)–1.8Δ0 + 3PCorrect answer is option 'C'. Can you explain this answer?
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If Δ0 is the octahedral splitting energy and P is the electron pairing energy, then the crystal-field stabilization energy [CFSE) of [Co(NH3)6]2+ is:a)–0.8Δ0 + 2Pb)–0.8Δ0 + 1Pc)–0.8Δ0d)–1.8Δ0 + 3PCorrect answer is option 'C'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about If Δ0 is the octahedral splitting energy and P is the electron pairing energy, then the crystal-field stabilization energy [CFSE) of [Co(NH3)6]2+ is:a)–0.8Δ0 + 2Pb)–0.8Δ0 + 1Pc)–0.8Δ0d)–1.8Δ0 + 3PCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If Δ0 is the octahedral splitting energy and P is the electron pairing energy, then the crystal-field stabilization energy [CFSE) of [Co(NH3)6]2+ is:a)–0.8Δ0 + 2Pb)–0.8Δ0 + 1Pc)–0.8Δ0d)–1.8Δ0 + 3PCorrect answer is option 'C'. Can you explain this answer?.
If Δ0 is the octahedral splitting energy and P is the electron pairing energy, then the crystal-field stabilization energy [CFSE) of [Co(NH3)6]2+ is:a)–0.8Δ0 + 2Pb)–0.8Δ0 + 1Pc)–0.8Δ0d)–1.8Δ0 + 3PCorrect answer is option 'C'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about If Δ0 is the octahedral splitting energy and P is the electron pairing energy, then the crystal-field stabilization energy [CFSE) of [Co(NH3)6]2+ is:a)–0.8Δ0 + 2Pb)–0.8Δ0 + 1Pc)–0.8Δ0d)–1.8Δ0 + 3PCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If Δ0 is the octahedral splitting energy and P is the electron pairing energy, then the crystal-field stabilization energy [CFSE) of [Co(NH3)6]2+ is:a)–0.8Δ0 + 2Pb)–0.8Δ0 + 1Pc)–0.8Δ0d)–1.8Δ0 + 3PCorrect answer is option 'C'. Can you explain this answer?.
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If Δ0 is the octahedral splitting energy and P is the electron pairing energy, then the crystal-field stabilization energy [CFSE) of [Co(NH3)6]2+ is:a)–0.8Δ0 + 2Pb)–0.8Δ0 + 1Pc)–0.8Δ0d)–1.8Δ0 + 3PCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for If Δ0 is the octahedral splitting energy and P is the electron pairing energy, then the crystal-field stabilization energy [CFSE) of [Co(NH3)6]2+ is:a)–0.8Δ0 + 2Pb)–0.8Δ0 + 1Pc)–0.8Δ0d)–1.8Δ0 + 3PCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of If Δ0 is the octahedral splitting energy and P is the electron pairing energy, then the crystal-field stabilization energy [CFSE) of [Co(NH3)6]2+ is:a)–0.8Δ0 + 2Pb)–0.8Δ0 + 1Pc)–0.8Δ0d)–1.8Δ0 + 3PCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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