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Which of the following amine gives diazonium salt on reaction with HNO2?
  • a)
    (CH3)2NH
  • b)
    CH3NH2
  • c)
    C6H5NH2
  • d)
    (CH3)3N
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Which of the following amine gives diazonium salt on reaction with HNO...
C6H5NH2 reacts with HNO2 to forms diazonium salts, the reaction are as follows,
C6H5NH2 + HNO2 ------> C6H5OH + H2O + N2
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Most Upvoted Answer
Which of the following amine gives diazonium salt on reaction with HNO...
C6H5NH2 reacts with HNO2 to forms diazonium salts, the reaction are as follows,
C6H5NH2 + HNO2 ------> C6H5OH + H2O + N2
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Community Answer
Which of the following amine gives diazonium salt on reaction with HNO...
Understanding Diazonium Salts
Diazonium salts are important intermediates in organic chemistry, often used in azo coupling reactions. The formation of diazonium salts involves the reaction of aromatic amines with nitrous acid (HNO2).
Key Amine Candidates
Among the options given:
- (CH3)2NH (Dimethylamine)
- CH3NH2 (Methylamine)
- C6H5NH2 (Aniline)
- (CH3)3N (Trimethylamine)
Why C6H5NH2 (Aniline)?
- Aromatic Nature: Aniline (C6H5NH2) is an aromatic amine, which is crucial for diazonium salt formation. Aromatic amines can stabilize the positive charge that forms during the diazotization process.
- Reaction with HNO2: When aniline reacts with nitrous acid (HNO2), it forms a diazonium salt (C6H5N2+Cl-). This reaction occurs at low temperatures (0-5°C) to prevent decomposition.
Other Options Explained
- (CH3)2NH (Dimethylamine): This is a secondary aliphatic amine and does not form diazonium salts as it lacks the aromatic structure necessary for stabilization.
- CH3NH2 (Methylamine): This is a primary aliphatic amine and also cannot form a stable diazonium salt due to the absence of an aromatic ring.
- (CH3)3N (Trimethylamine): This is a tertiary amine and similarly does not provide the necessary conditions for diazonium formation.
Conclusion
In summary, C6H5NH2 (aniline) is the only amine among the options that can successfully react with nitrous acid to form a diazonium salt, making it the correct answer to the question.
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