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A mixture contains coarse aggregates (GS = 2.7), fine aggregates (GS = 2.9), Mineral filler (GS = 1.5) in the proportion 50:40:10 (by weight). These materials are mixed with bitumen (GS = 1.2) and compacted, the unit
weight becomes 2300 Kg/m3 and contains 5% voids. Calculate the voids in mineral aggregates for the given specimen?
weight becomes 2300 Kg/m3 and contains 5% voids. Calculate the voids in mineral aggregates for the given specimen?
- a)5%
- b)10%
- c)15%
- d)20%
Correct answer is option 'C'. Can you explain this answer?
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A mixture contains coarseaggregates (GS = 2.7), fineaggregates (GS = 2...
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A mixture contains coarseaggregates (GS = 2.7), fineaggregates (GS = 2...
To calculate the voids in the mineral aggregates for the given specimen, we need to determine the volume of each component and the total volume of the mixture.
1. **Given data:**
- Coarse aggregates GS = 2.7
- Fine aggregates GS = 2.9
- Mineral filler GS = 1.5
- Proportion by weight: 50:40:10 (coarse aggregates: fine aggregates: mineral filler)
- Bitumen GS = 1.2
- Unit weight of compacted mixture = 2300 Kg/m3
- Voids in the mixture = 5%
2. **Calculating the volume of each component:**
- Let's assume the total weight of the mixture is 100 units.
- Therefore, the weight of coarse aggregates = 50 units, fine aggregates = 40 units, and mineral filler = 10 units.
- The volume of each component can be calculated using the formula: Volume = (Weight of component) / (Specific gravity x Unit weight of water)
- Volume of coarse aggregates = (50 / (2.7 x 1000)) m3
- Volume of fine aggregates = (40 / (2.9 x 1000)) m3
- Volume of mineral filler = (10 / (1.5 x 1000)) m3
3. **Calculating the total volume of the mixture:**
- Total volume of the mixture = Volume of coarse aggregates + Volume of fine aggregates + Volume of mineral filler + Volume of bitumen
- Bitumen volume can be calculated using the formula: Volume = (Weight of bitumen) / (Specific gravity x Unit weight of water)
- Let's assume the weight of bitumen = x units (out of 100 units)
- Volume of bitumen = (x / (1.2 x 1000)) m3
- Total volume of the mixture = Volume of coarse aggregates + Volume of fine aggregates + Volume of mineral filler + Volume of bitumen
4. **Calculating the voids in the mineral aggregates:**
- Voids in the mixture = (Total volume of the mixture - Volume of all components) / Total volume of the mixture
- We know that voids in the mixture = 5% and the volume of bitumen is negligible compared to the other components.
- Therefore, the voids in the mineral aggregates can be approximated as:
Voids in mineral aggregates = (Voids in the mixture) - (Voids due to bitumen)
Voids in mineral aggregates = 5% - 0%
Voids in mineral aggregates = 5%
Hence, the voids in the mineral aggregates for the given specimen is approximately 5%. Therefore, option (a) is the correct answer.
1. **Given data:**
- Coarse aggregates GS = 2.7
- Fine aggregates GS = 2.9
- Mineral filler GS = 1.5
- Proportion by weight: 50:40:10 (coarse aggregates: fine aggregates: mineral filler)
- Bitumen GS = 1.2
- Unit weight of compacted mixture = 2300 Kg/m3
- Voids in the mixture = 5%
2. **Calculating the volume of each component:**
- Let's assume the total weight of the mixture is 100 units.
- Therefore, the weight of coarse aggregates = 50 units, fine aggregates = 40 units, and mineral filler = 10 units.
- The volume of each component can be calculated using the formula: Volume = (Weight of component) / (Specific gravity x Unit weight of water)
- Volume of coarse aggregates = (50 / (2.7 x 1000)) m3
- Volume of fine aggregates = (40 / (2.9 x 1000)) m3
- Volume of mineral filler = (10 / (1.5 x 1000)) m3
3. **Calculating the total volume of the mixture:**
- Total volume of the mixture = Volume of coarse aggregates + Volume of fine aggregates + Volume of mineral filler + Volume of bitumen
- Bitumen volume can be calculated using the formula: Volume = (Weight of bitumen) / (Specific gravity x Unit weight of water)
- Let's assume the weight of bitumen = x units (out of 100 units)
- Volume of bitumen = (x / (1.2 x 1000)) m3
- Total volume of the mixture = Volume of coarse aggregates + Volume of fine aggregates + Volume of mineral filler + Volume of bitumen
4. **Calculating the voids in the mineral aggregates:**
- Voids in the mixture = (Total volume of the mixture - Volume of all components) / Total volume of the mixture
- We know that voids in the mixture = 5% and the volume of bitumen is negligible compared to the other components.
- Therefore, the voids in the mineral aggregates can be approximated as:
Voids in mineral aggregates = (Voids in the mixture) - (Voids due to bitumen)
Voids in mineral aggregates = 5% - 0%
Voids in mineral aggregates = 5%
Hence, the voids in the mineral aggregates for the given specimen is approximately 5%. Therefore, option (a) is the correct answer.
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A mixture contains coarseaggregates (GS = 2.7), fineaggregates (GS = 2.9), Mineral filler(GS = 1.5) in the proportion50:40:10 (by weight). Thesematerials are mixed with bitumen(GS = 1.2) and compacted, the unitweight becomes 2300 Kg/m3 andcontains 5% voids. Calculate thevoids in mineral aggregates for thegiven specimen?a)5%b)10%c)15%d)20%Correct answer is option 'C'. Can you explain this answer?
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A mixture contains coarseaggregates (GS = 2.7), fineaggregates (GS = 2.9), Mineral filler(GS = 1.5) in the proportion50:40:10 (by weight). Thesematerials are mixed with bitumen(GS = 1.2) and compacted, the unitweight becomes 2300 Kg/m3 andcontains 5% voids. Calculate thevoids in mineral aggregates for thegiven specimen?a)5%b)10%c)15%d)20%Correct answer is option 'C'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A mixture contains coarseaggregates (GS = 2.7), fineaggregates (GS = 2.9), Mineral filler(GS = 1.5) in the proportion50:40:10 (by weight). Thesematerials are mixed with bitumen(GS = 1.2) and compacted, the unitweight becomes 2300 Kg/m3 andcontains 5% voids. Calculate thevoids in mineral aggregates for thegiven specimen?a)5%b)10%c)15%d)20%Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A mixture contains coarseaggregates (GS = 2.7), fineaggregates (GS = 2.9), Mineral filler(GS = 1.5) in the proportion50:40:10 (by weight). Thesematerials are mixed with bitumen(GS = 1.2) and compacted, the unitweight becomes 2300 Kg/m3 andcontains 5% voids. Calculate thevoids in mineral aggregates for thegiven specimen?a)5%b)10%c)15%d)20%Correct answer is option 'C'. Can you explain this answer?.
A mixture contains coarseaggregates (GS = 2.7), fineaggregates (GS = 2.9), Mineral filler(GS = 1.5) in the proportion50:40:10 (by weight). Thesematerials are mixed with bitumen(GS = 1.2) and compacted, the unitweight becomes 2300 Kg/m3 andcontains 5% voids. Calculate thevoids in mineral aggregates for thegiven specimen?a)5%b)10%c)15%d)20%Correct answer is option 'C'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A mixture contains coarseaggregates (GS = 2.7), fineaggregates (GS = 2.9), Mineral filler(GS = 1.5) in the proportion50:40:10 (by weight). Thesematerials are mixed with bitumen(GS = 1.2) and compacted, the unitweight becomes 2300 Kg/m3 andcontains 5% voids. Calculate thevoids in mineral aggregates for thegiven specimen?a)5%b)10%c)15%d)20%Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A mixture contains coarseaggregates (GS = 2.7), fineaggregates (GS = 2.9), Mineral filler(GS = 1.5) in the proportion50:40:10 (by weight). Thesematerials are mixed with bitumen(GS = 1.2) and compacted, the unitweight becomes 2300 Kg/m3 andcontains 5% voids. Calculate thevoids in mineral aggregates for thegiven specimen?a)5%b)10%c)15%d)20%Correct answer is option 'C'. Can you explain this answer?.
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A mixture contains coarseaggregates (GS = 2.7), fineaggregates (GS = 2.9), Mineral filler(GS = 1.5) in the proportion50:40:10 (by weight). Thesematerials are mixed with bitumen(GS = 1.2) and compacted, the unitweight becomes 2300 Kg/m3 andcontains 5% voids. Calculate thevoids in mineral aggregates for thegiven specimen?a)5%b)10%c)15%d)20%Correct answer is option 'C'. Can you explain this answer?, a detailed solution for A mixture contains coarseaggregates (GS = 2.7), fineaggregates (GS = 2.9), Mineral filler(GS = 1.5) in the proportion50:40:10 (by weight). Thesematerials are mixed with bitumen(GS = 1.2) and compacted, the unitweight becomes 2300 Kg/m3 andcontains 5% voids. Calculate thevoids in mineral aggregates for thegiven specimen?a)5%b)10%c)15%d)20%Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of A mixture contains coarseaggregates (GS = 2.7), fineaggregates (GS = 2.9), Mineral filler(GS = 1.5) in the proportion50:40:10 (by weight). Thesematerials are mixed with bitumen(GS = 1.2) and compacted, the unitweight becomes 2300 Kg/m3 andcontains 5% voids. Calculate thevoids in mineral aggregates for thegiven specimen?a)5%b)10%c)15%d)20%Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A mixture contains coarseaggregates (GS = 2.7), fineaggregates (GS = 2.9), Mineral filler(GS = 1.5) in the proportion50:40:10 (by weight). Thesematerials are mixed with bitumen(GS = 1.2) and compacted, the unitweight becomes 2300 Kg/m3 andcontains 5% voids. Calculate thevoids in mineral aggregates for thegiven specimen?a)5%b)10%c)15%d)20%Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice Civil Engineering (CE) tests.
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