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Eight small drops each of radius r and having same charge q combines to form a bigger sphere.the ration between the potential of bigger drop to smaller drop is:?
Most Upvoted Answer
Eight small drops each of radius r and having same charge q combines t...
Explanation:

When eight identical small drops of radius r combine to form a bigger sphere, the charge on each small drop remains the same. Therefore, the total charge on the bigger sphere is 8q, where q is the charge on each small drop.

Calculating the potential:

The potential of a sphere of radius R and charge q is given by the formula V = (1/4πε) (q/R), where ε is the permittivity of the medium.

Calculating the potential of bigger sphere:

Using the above formula, the potential of the bigger sphere can be calculated as V1 = (1/4πε) (8q/R1), where R1 is the radius of the bigger sphere.

Calculating the potential of smaller sphere:

Similarly, the potential of a small drop of radius r and charge q can be calculated as V2 = (1/4πε) (q/r).

Calculating the ratio of potentials:

Dividing V1 by V2, we get:
V1/V2 = (8q/R1) / (q/r)
V1/V2 = 8R/r

Therefore, the ratio of potential of the bigger sphere to that of a smaller drop is 8 times the ratio of their radii.
Community Answer
Eight small drops each of radius r and having same charge q combines t...
8q÷2r potential of bigger oneQ÷r potential of small oneSo ratio is 4
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Eight small drops each of radius r and having same charge q combines to form a bigger sphere.the ration between the potential of bigger drop to smaller drop is:?
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